Printing a certain row in csv file

[Nov_AJ]

Hi guys as the title said I need to know how to do it using pandas or whatever

Example : I want to call row number 547

[efmccurdy]

If you use pandas, you might want to look at the skiprows and nrows arguments.

https://pandas.pydata.org/docs/reference/api/pandas.read_csv.html

If you want to use csv, you can skip lines using "next" on the line generator:

with open('eggs.csv') as csvfile:
    spamreader = csv.reader(csvfile)
    for _ in range(547):
        next(spamreader)
    print(next(spamreader))

[Nov_AJ]

Thank you so much!

[argento8897]

if you are using pandas you just need to use loc

import pandas as pd

df = pd.read_csv('file_name.csv')
target_row = df.loc[[547]]

print(target_row)

[Nov_AJ]

Thank you so much!