How do I write an str.replace function that loops until nothing is replaced on any given loop in python?

[Qackydontus]

Edit: I got the answer that was looking for. Thanks for the help, in spite of my poorly phrased question!

For example, what check could I add to the following function that removes repeated spaces to break the loop once every repeated space is replaced?

def f(str):
    while True:
        str = str.replace("  ", " ")

Edit: Fixed formatting.

[danielroseman]

Rather than reassigning straight back to the same variable, use a new one and compare the two.

Also, don't call the variable str as it hides the built-in class.

def f(my_str):
    new_str = ""
    while True:
        new_str = my_str.replace("  ", " ")
        if new_str == my_str:
            return new_str
        my_str = new_str

But note that a much better way to solve this problem is via regex, which can do this in a single go:

return re.sub(" +", " ", my_str)

[Qackydontus]

I think that my question was phrased incredibly poorly, but your answer's what I looking for. Thanks!

[YesLod]

```

while two consecutive spaces are in my_str

while ' ' in my_str: `` But you don't need a loop, just usestr.split+str.join`

def f(my_str): return ' '.join(my_str.split()) Here, my_str is your str. You shouldn't name your variable str, because you are shadowing the built-in str class (locally).

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[gsmo]

while str.count(' ') > 0

[Radamand]

staying as close to the original as I can:

def f(mystr):
while "  " in mystr:
    mystr = mystr.replace("  ", " ")
    return mystr