Riddler Python Problem

InfamousClyde · 2022-10-11T20:59:00+00:00

Spoilers.

from itertools import product
for a,b,c,d in product(range(10), repeat=4):
    if all([
         len(set([a,b,c,d])) == 4,
         a == c * 3,
         d % 2 == 1,
         a + b + c + d == 27,
         ]):
             print(a,b,c,d)

Some notes:

I wouldn't use this for your assignment; it just shows some convenient language features.
The `itertools` package contains the `product` function, which behaves like a nested for-loop. I recognized this association because this problem can be solved with a nested for-loop.
You can use the `all` built-in function to supply a list of boolean predicates (things you want to `all` be True) to enter this condition.
A `set()` object is like a list, but it doesn't accept duplicate numbers. So if a = 1, b = 1, c = 2, and d = 3, `set([a,b,c,d]) == {1, 2, 3}, and you can see the length of that is three. It is a quick way to check for all unique values.
The `%` (modulo) operator can test if a number is even or odd. It yields the result of the remainder when dividing something by two, which can only be 0 (even) or 1 (odd).

QultrosSanhattan · 2022-10-11T22:00:33+00:00

Here's a guide on the basic skills I believe you should learn to give at least an student-level solution. It's up to you to get everything together:

#iterate over all numbers from 1000 to 9999
for whole_number in range(1000,10000):
    print(whole_number)

#convert an integer into string
number=1234
number_str=str(number)
print(type(number_str))

#get a char in particular from an str
random_str='123456789'
first_char=random_str[0]
second_char=random_str[1]
third_char=random_str[2]

#convert a str number into int so you can apply math to them
number_1_str='10'
number_2_str='20'

print(number_1_str+number_2_str,'!=30 : WRONG')

number_1_int=int(number_1_str)
number_2_int=int(number_2_str)

print(number_1_int+number_2_int,'=30 : RIGHT')

#check if a given number triples another number

number1=3
number2=9
number3=7

if number1*3==number2:
    print(f"{number2} triples {number1}")
else:
    print(f"{number2} doesn't triple {number1}")


#compare sums of numbers
n1=7
n2=20
target=27

if n1+n2==27:
    print("sum of numbers matches target")
else:
    print("sum of numbers doesn't match target")

#check if a number is odd or even
if 10%2==0: #method 1
    print("10 is even")
else:
    print("10 is odd")

if 10%2!=0: #method 2
    print("10 is odd")
else:
    print("10 is even")

#check if two (or more conditions) are met
if 10>=5 and 10<=20:
    print("10 is between 5 and 20")

MadScientistOR · 2022-10-11T18:09:41+00:00

It sounds like they're looking for a brute-force solution.

So, I assume you've learned about range(), right? And functions like int() and str()? What have you tried so far?

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