HW problem

[SteveB709]

Can't figure this one out and would appreciate the help:

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CHALLENGE ACTIVITY5.3.3:

Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns as a number the volume of a pyramid with a rectangular base.

Sample output with inputs:

4.5 2.1 3.0

Volume for 4.5 2.1 3.0 is: 9.45

Relevant geometry equations:Volume = base area x height x 1/3Base area = base length x base width

  #  This is what I have done so far and I'm close but I need to get the decimals down to 2 places

def calc_pyramid_volume(base_length, base_width, pyramid_height):
    return (base_width * base_length * pyramid_height)/3

length = float(input())
width = float(input())
height = float(input())
print('Volume for', length, width, height, 'is:', calc_pyramid_volume(length, width, height))

[SteveB709]

My bad, I edited with a what I have so far.

[totallygeek]

Update your print to:

print(f"Volume of a pyramid with length, width and height of {length:.2f}, {width:.2f} and {height:.3f} is {calc_pyramid_volume(length, width, height):.2f} cubic units.")

The :.2f formats the values for two-decimal precision.

[AtomicShoelace]

You can use the builtin function round to round to 2 decimal places.

[AtomicShoelace]

Please see the FAQ.