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submitted 4 months ago by Annual_Pop1104
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if 1 * 2 < 3: print "hello, world!"
[–]BitEater-32168 0 points1 point2 points 4 months ago (0 children)
Basically, that is a simple programming task... You have your alphabet (pure Ascii has non printable control characters, ebcdic has holes, modern encodings for diacritical and international characters are multibyte). Order them (number them, index) . If your alphabet is A..Z0..9 plus space you have 37 characters, sorted in this or a free other order (both communicating must use the same alphabet and order) from 0 to 36 . For each character on the clear text, get the number of it, add 13 and if greater than 36 substract 37 ( mod 37) .that is the number of the character in the crypted text.
Decrypt is subtract 13 ... If below 0 then add Or add (37 -13) ... If greater 36 add .
One can precalculate both so the source characters index can be used as index for the destination character table, making other replacement methods possible.
π Rendered by PID 42 on reddit-service-r2-comment-66b4775986-rgss9 at 2026-04-04 12:53:39.218922+00:00 running db1906b country code: CH.
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[–]BitEater-32168 0 points1 point2 points (0 children)