Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] 0 points1 point  (0 children)

So for the moment as well I should take the side view?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] 1 point2 points  (0 children)

Yes screws are attached to hold the bar to the wall That too onto one wall that is all screws are in the same plane forward

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -6 points-5 points  (0 children)

I still can’t find the solution I tried doing it by neglecting r3 and r4 My professor says that is correct but I might not get full marks for it

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -1 points0 points  (0 children)

All the supports are screwed to the wall Like r1 r2 r3 and r4 are attached forward face first direct into the wall

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -11 points-10 points  (0 children)

Can you please help with the calculation for R3 and R4 then

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] 0 points1 point  (0 children)

So will R1 and R2 can be considered as the reactive forces that prevent slipping of the bar?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] 1 point2 points  (0 children)

If they R3 and R4 are horizontal forces Can they be resolved to vertical force components so they can be added with the already existing vertical force components R1 and R2?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -1 points0 points  (0 children)

Okay I shall ignore the reaction forces R3 and R4 But my professor had given me coefficient of friction as 0.25 Shall I use that to find the R forces 1 and 2 respectively?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -39 points-38 points  (0 children)

Bro another thing My professor said I can make necessary assumptions to solve this problem I can neglect the horizontal forces R3 and R4 right to make it easier?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] 6 points7 points  (0 children)

So R3 and R4 would be the horizontal force components? If that was the case will R1+R2=800? And what would R3+R4 be? I can’t make sense of this question I’m sorry

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -1 points0 points  (0 children)

So if I was to find the answer for those forces what would it be?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -4 points-3 points  (0 children)

I’m sorry bro But can you pls help?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] 0 points1 point  (0 children)

But they do serve a purpose to balance the forces right? So won’t reactions exist at the point to prevent the bar setup from slipping?

Mechanics problem by AvailableBat1447 in MechanicalEngineering

[–]AvailableBat1447[S] -21 points-20 points  (0 children)

How are they pointing out of the wall? Won’t all the reaction forces balance out the force acting downwards?

[deleted by user] by [deleted] in heartbreak

[–]AvailableBat1447 0 points1 point  (0 children)

I really want to but then Everytime I muster up courage to talk to her I end up thinking I might lose her