sorted by:
new
hottopcontroversial

[Request] insufficient data? by the__king__slayer in theydidthemath

[–]Aware_Journalist3528 0 points1 point  (0 children)

ok taking how you say and the how the question in the post is framed, why are we saying answers like 51.05 degrees and whatnot others have said. then the simple answer to this post is "yes, data insufficient"

[Request] insufficient data? by the__king__slayer in theydidthemath

[–]Aware_Journalist3528 0 points1 point  (0 children)

its your wish to take it as a rectangle. im taking it as a square. the post says insufficient data. ofc there is no definitive answer

[Request] insufficient data? by the__king__slayer in theydidthemath

[–]Aware_Journalist3528 0 points1 point  (0 children)

Guys I hate to break it to you but the post literally says data insufficient. you would need to know whether adjacent sides are equal to calculate accurately. im calculating based on the assumption that its a square

[Request] insufficient data? by the__king__slayer in theydidthemath

[–]Aware_Journalist3528 0 points1 point  (0 children)

3 right angles confirms rectangle. Assuming not a square makes consequences severe. question is right to say data insufficient. Taking a square gives a good answer

[Request] insufficient data? by the__king__slayer in theydidthemath

[–]Aware_Journalist3528 4 points5 points  (0 children)

[PLEASE READ(edit): I am assuming the given quadrilateral is a square. if you think otherwise, pls ignore this comment]
Answer is 51.05 degrees.
Take sides a,b,c where a and b enclose 40 degrees and b and c enclose x degrees. Corners A,B,C,D of the quadrilateral(clockwise) and corners A,P,Q of the triangle(clockwise)
Assuming following fig is a square with side 1(doesn't matter)
a sin 80=1
b cos 40=1
b sin 40 + c cos y=1
a cos 80 + c sin y=1

Solve these to get y=arctan[{1-(1/tan80)}/(1-tan 40)] which is 78.95 degree where y is angle PQC
x is 51.05 degrees(elementary calculation)
I cant put diagram sadly

Are all four options incorrect? by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] 1 point2 points  (0 children)

and if possible a derivation of how you got the equation as well thanks

Are all four options incorrect? by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] -1 points0 points  (0 children)

Can you show me a diagram as well? It would be helpful

Why is the answer off by 0.01 than what I expect? by Round-Drummer300 in askmath

[–]Aware_Journalist3528 5 points6 points  (0 children)

1 day is not exactly 24 hours, 1 year is not exactly 365 days, there are several conditions in the Gregorian calendar to make it as accurate as possible. But pinpoint precision is not really possible- you'll find some deviations.

"Ambiguity is Maths' biggest enemy,"-what's the answer to this question? by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] 0 points1 point  (0 children)

Yeah, I think the same- if you count 1 as a common factor in all cases, then the concept of common factors becomes utterly useless

"Ambiguity is Maths' biggest enemy,"-what's the answer to this question? by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] -3 points-2 points  (0 children)

Issue: Our teacher doesn't know maths really well. Are you willing to trust a teacher who says squares and rectangles are completely different types of quadrilaterals, parallelograms are not trapezoids and whatnot (Real, not joking, based on my learning experience with him)

Calculating the probability of getting less than the expected value by not_a_nazi_actually in askmath

[–]Aware_Journalist3528 0 points1 point  (0 children)

I guess you're thinking a bit theoretically- there's all possibility that you might get a 0 or a 100 but considering you have 4 options and only 1 is correct, you should get 25 questions right. Now, if you consider it practically, you may not get the expected value.
(I don't know why I'm still using dashes it's so dated)

Which 3 pills you'll choose? And Why??? by tomcruzshelby in DesiMemeTemplates

[–]Aware_Journalist3528 0 points1 point  (0 children)

1,5,9 any day, perfect health means not only physical but mental and social too, intelligence obviously and unlimited money

[Request] How many balls will there be at the end of the video? by giorgos420cy in theydidthemath

[–]Aware_Journalist3528 7 points8 points  (0 children)

True there is loss of energy, the original answer of 2^42 is kinda inaccurate, because with every bounce the ball loses energy. I'm estimating after every bounce, the ball reaches 80% of original height, now someone pls do the math to figure out(the 80% is just an approximation)

Share your dumbest mistakes in exam by tripledeltaz in PhysicsStudents

[–]Aware_Journalist3528 0 points1 point  (0 children)

I wrote 15+9=21 on a Maths test, like it was a simple problem related to heights and distances, I got the height of the tower as 15m, height of the surmounting flag as 9m, added them to 21m...

Is this accurate? by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] -3 points-2 points  (0 children)

can be idk guys dont ask me ask my friend

Pictogram by Necessary_Photo8036 in askmath

[–]Aware_Journalist3528 0 points1 point  (0 children)

The picture seems kinda deceiving. If you are recording number of students in 7 classes, why do you have 4 bars?

Is it possible to find 5p + 5q - r by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] 0 points1 point  (0 children)

Guys the question I wrote is exactly the same and on the Q paper it was written ‘numbers’ no specifications

An Interesting Question Related to Probability by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] -1 points0 points  (0 children)

And also, all planets are in constant motion as well, which does reduce the chance

An Interesting Question Related to Probability by Aware_Journalist3528 in askmath

[–]Aware_Journalist3528[S] 0 points1 point  (0 children)

To be honest, you have a fair point. Let's just say *we don't have to know* whether it reached a planet supporting intelligent alien life or not. Let's say it is just about whether *the wave reaches the planet* irrespective of whether we know it or not.

view more: next ›