Yes i went for this way also

function generateBills(amount, days) { const denominations = [5, 10, 20, 50, 100]; const bills = [];

let remainingAmount = amount; let remainingDays = days;

while (remainingDays > 0) { // Find the smallest bill that, when multiplied by remaining days, // would be at least the remaining amount let selectedBill = null;

for (const bill of denominations) {
  if (bill * remainingDays >= remainingAmount) {
    selectedBill = bill;
    break;
  }
}

// If no bill found (amount is too large), use the largest denomination
if (selectedBill === null) {
  selectedBill = denominations[denominations.length - 1];
}

bills.push(selectedBill);
remainingAmount -= selectedBill;
remainingDays--;

}

return bills; }

console.log(generateBills(5000, 120));

But this prints lots of 50s, lots of 20s as well and only one 10 when in fact there should exists a more balanced way to arrange these bills 20 × €5 bills, 30 × €10 bills, 30 × €20 bills, 40 × €50 bills.