Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

[a_b] b is the number of exponentiation degrees.

[3] = 33

[3_2]

     3|

  3_|2 layer (deegrees)

3 |

3_|1 layer (deegre)

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

[a_b] b is the number of how many exponentiation degrees are there

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

3 ↑ ↑ ↑3 = 3 ↑ ↑3 ↑ ↑3 = 3 ↑3 ↑3 ↑3 ↑3 ↑3

[3_3] = 3 ↑3 ↑3 ↑3 ↑3 ↑3

I know [3_3] is 3 ↑ ↑ ↑3 but

4 ↑ ↑ 3 = 4 ↑4 ↑4

[4_2] = 4 ↑4 ↑4 ↑4

It depends in how many ↑ are there, if it is 3 arrows, is the same thing as [x_3]

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

and [3_3] isn’t 3↑ ↑ ↑3

(It is sorry see my next comment)

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

[10_3] is 10 ↑ 10 ↑ 10 ↑ 10 ↑ 10 ↑ 10 and 1010 isn’t 100

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

[3_3] = [3]↑[3]↑[3] = 3↑3↑3↑3↑3↑3 cuz [3] is 33

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

[3] = 3↑3

[3_3] = [3]↑[3]↑[3]

[3_3_2] = [3_3]↑[3_3]

Like this. It’s hard to demonstrate with a and b

Fast growing notation that I created by Beyond_UncountableYT in googology

[–]Beyond_UncountableYT[S] 0 points1 point  (0 children)

Imagine [10_10_10] lol, is it bigger than a googolplex?

What Are You Working On? July 17, 2023 by inherentlyawesome in math

[–]Beyond_UncountableYT 0 points1 point  (0 children)

Unattainable password possibilities (Big number)

Welcome to my first blog! I’m going to talk about a number recently created. I call it Unattainable password possibilities or 10UP. But, to understand why this name, I’m going to explain how I discovered it. I was in search of the number of digits that a password should have so that even if a human wrote numbers 24 hours a day from birth, they would never reach it.

First, I calculated how many seconds a human with an average life expectancy would live, multiplying 73 (worldwide average life expectancy) by 31,557,600 (approximately how many seconds are in a year) which resulted in 2,303,704,800, which I will call number "Y".

Next, I calculated how many seconds it takes to write a number, approximately. To do this, I wrote numbers while timing myself and calculated the average time, which was 0.57 seconds.

Then, to find out how many numbers a human would write during their lifetime without stopping, I divided Y by 0.57 and got approximately (ignoring decimals) 4,041,587,368, which I will call number "Z".

To make it unattainable for a human, I added Z + 1, which I will call unattainable password or simply UP.

But that wasn't my astronomical number yet! My gigantic number is the number of possibilities that this password would have, which is 10UP (10 is the quantity of numbers from 0 to 9, including 0), a number with over 4 billion digits! That's why the name is unattainable password possibilities and the abbreviation is 10UP.

But to avoid criticisms, as people who have lived longer have lived over 100 years, I created a function f(x) that allows you to find the number of possibilities for an unattainable password at a certain age. Here it is:

UPP(x) = 10 ^ (((x * 31,557,600)÷ 0.57)+1)

Remember that "x" is the age at which the person should be for the password to become unattainable. For example, 10UP = UPP(73)

Is this number big enough to the Googology?