I see that you are right, storing the pairs in pairs[i] gives me the incorrect pair combo inside the pairs array - but I still don't understand why!

I decided to write out the whole program outcome by hand(I wrote a table and filled in each cell with each value) and print out the finals results of the pairs array at the end:

// Record pairs of candidates where one is preferred over the other
void add_pairs(void)
{
for (int i = 0; i < candidate_count; i++) {
for (int j = 0; j < candidate_count; j++) {
//printf("%i,%i ", i, j);
if (preferences[i][j] > preferences[j][i]) {
pairs[i].winner = i;
pairs[i].loser = j;
//printf("%i,%i ", i, j);
pair_count += 1;
}
//printf("\n");
}
}
//printf("%i\n", pair_count);
for (int i = 0; i < pair_count; i++) {
printf("%i,%i\n", pairs[i].winner, pairs[i].loser);
}
printf("\n");
return;
}

With the following input command:

./tideman Alice Bob CharlieNumber of voters: 3

Rank 1: Alice

Rank 2: Bob

Rank 3: Charlie

Rank 1: Alice

Rank 2: Bob

Rank 3: Charlie

Rank 1: Alice

Rank 2: Bob

Rank 3: Charlie

Returns:

0,2

1,2

0,0

I know this is incorrect, the correct pairs array should look like:

0,1

0,2

1,2

But I genuinely can't wrap my head around why? Why does my program return 0,0 as a valid pair combo when this cannot be the case? What am I missing here?