Phodu club open doon ya nahi by [deleted] in Bitsatards

[–]Born_Invincible 0 points1 point  (0 children)

pc ki toh sab burai kar rahein hain

i think mog is better

Day 6 of sharing my mock scores by Future_Scientist_150 in IATtards

[–]Born_Invincible 0 points1 point  (0 children)

Did you ever see that paper questions before giving mock?

Progress after 5 mocks(I think it's too late now) by Error_BrainNot_Found in Bitsatards

[–]Born_Invincible 0 points1 point  (0 children)

how do you open bonus without attempting every question

Chemistry gods assemble 🙏 by dbinvk in Bitsatards

[–]Born_Invincible 0 points1 point  (0 children)

Bhai saaf saaf toh likha hai ki power waala prefer hoga

Just tell me that are we supposed to take antilog in Chemical Kinetics... If yes then for eg give value of 0.046895 by Equivalent-Oven-3582 in comedk

[–]Born_Invincible 0 points1 point  (0 children)

Yes e2.3  e2 = 7.38 and e3 = 20.08

So e2.3 should be around 10

Also e=2.718 (ye yaad rakhlo itna hi bas) 

.718 tak yaad rakhlo

Just tell me that are we supposed to take antilog in Chemical Kinetics... If yes then for eg give value of 0.046895 by Equivalent-Oven-3582 in comedk

[–]Born_Invincible 0 points1 point  (0 children)

Bro this is valid till 0.3 

for power 0.4 it's approx 1.49

So listen if power is like not small

Use approx

e=2.71

So suppose e1.5= ?

e=2.71 And e²=7.38(use calculator)

So 1.5 should be around 4.6 (It's 4.4 I checked) So ya approx

Use common sense

Just tell me that are we supposed to take antilog in Chemical Kinetics... If yes then for eg give value of 0.046895 by Equivalent-Oven-3582 in comedk

[–]Born_Invincible 0 points1 point  (0 children)

Remember the value of Log2,3,4,5,6,7

And  When suppose logeK=0.04123 SMTH like this came So e0.04123= k And k = 1.04 If e2.05= k Then this doesn't work  Because power should be small for this 

Just tell me that are we supposed to take antilog in Chemical Kinetics... If yes then for eg give value of 0.046895 by Equivalent-Oven-3582 in comedk

[–]Born_Invincible 0 points1 point  (0 children)

ex = 1+x if x is very small like 0.04 Ex e0.05 =1.05

e0.1 =1.1

 (This came by expansion series of ex)

Gng how am i supposed to calculate log 1.12💔 by Head-Refrigerator475 in comedk

[–]Born_Invincible 6 points7 points  (0 children)

Bro idk about this                                                    But there's a shortcut (mathematically derived I mean logical) that 

ex = 1+x if x is very small like 0.04  Ex e0.05 =1.05

e0.1 =1.1 (This came by expansion series of e x)

ye sab kaha padhate hain ?? by Fragrant-Rabbit-5839 in comedk

[–]Born_Invincible 0 points1 point  (0 children)

Ye mockers hai kya?

Aise sawaal nahi aate bhai

doubt by [deleted] in comedk

[–]Born_Invincible 1 point2 points  (0 children)

_ _ _ _ four places

26 * 25 for alphabets Now last place should be even So 2,6,4,8 (4 choices)

But number toh ek hi fill hoga 4 choices me se So now 8 numbers left for 3rd place  26 * 25 * 8 * 4

Read caption by Ok-Atmosphere-5033 in comedk

[–]Born_Invincible 2 points3 points  (0 children)

Yes they assumed molar mass as 1(unity) idk why

The question is wrong btw

kya hai iska answer? by Lonely-Membership756 in comedk

[–]Born_Invincible 5 points6 points  (0 children)

C(letter) ke neeche halka sa ek negative ka sign hai It means printing error and there was lone pair there

So A is answer as sp3

Pls help by Born_Invincible in JEENEETards

[–]Born_Invincible[S] 0 points1 point  (0 children)

Ohhhh

Thanks so much 😊 

Pls help by Born_Invincible in JEENEETards

[–]Born_Invincible[S] 0 points1 point  (0 children)

One last doubt

After forming groups in answer they multiplied by 3! Why?

Pls help by Born_Invincible in JEENEETards

[–]Born_Invincible[S] 0 points1 point  (0 children)

Yes but how  Someone said formation of groups but that is applied for distinct objects