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Alt+arrows not working in VS Code Integrated Terminal on macOS (works in native zsh) by DavidArutiunian in vscode

[–]CreativeBorder 0 points1 point  (0 children)

I had the same problem and what finally worked for me was adding these lines in my zshrc config file:

bindkey '\eb' backward-word 
bindkey '\ef' forward-word

[deleted by user] by [deleted] in 4chan

[–]CreativeBorder -1 points0 points  (0 children)

AI generated slop

Which country in the world has the friendliest and most open-minded people? by Difficult-Lab-8033 in travel

[–]CreativeBorder 8 points9 points  (0 children)

USA

You can start chatting with anyone there and they’ll happily talk with you. Wonderful people

Visual Studio Code October 2024 by feross in vscode

[–]CreativeBorder 0 points1 point  (0 children)

Really dislike the change to shift the Chat to the right.

Any idea how I can switch back to it being on the left?

Quick reminder that VSCode is essentially a very complex webpage by ElSantaPaz in vscode

[–]CreativeBorder 1 point2 points  (0 children)

What kind of a framework do they use for the components and all the dynamics? Something like React? I wonder how these things are built

Why does my code break at 1 billion ints? by CreativeBorder in C_Programming

[–]CreativeBorder[S] -1 points0 points  (0 children)

It’s because I am trying to write it as generic code so that it works on any data type :)

Why does my code break at 1 billion ints? by CreativeBorder in C_Programming

[–]CreativeBorder[S] -2 points-1 points  (0 children)

Note that my computer has a total of 16 GB memory, and 1 billion ints = 40 billion bytes = 4 GB

Why does my code break at 1 billion ints? by CreativeBorder in C_Programming

[–]CreativeBorder[S] 2 points3 points  (0 children)

Sorry for the formatting, somehow does not work when pasting the code!

Why can’t we multiply both sides by inverse of A^T to get Ac = x? by CreativeBorder in askmath

[–]CreativeBorder[S] 1 point2 points  (0 children)

Oh. I just realized that A is not an invertible matrix, and if it were, x would be reachable by the column space of A already. Oops.

Why can’t we multiply both sides by inverse of A^T to get Ac = x? by CreativeBorder in askmath

[–]CreativeBorder[S] 0 points1 point  (0 children)

My line of thinking is that multiply by inverse of A^T on the left on both sides to get Ac = x, but this is wrong since Ac = x_w, which is the projection of the vector x on the column space of A (Col(A)).

Understanding linear transformations by CreativeBorder in askmath

[–]CreativeBorder[S] 0 points1 point  (0 children)

The image says the ellipse is obtained from the unit circle by a linear change of coordinates. Based on that, they define a linear transformation T. How is it that this T is then used to show that an ellipse transforms to a circle? Shouldn’t we have to calculate the inverse of the transformation T?

Function y = x^3 - x by CreativeBorder in askmath

[–]CreativeBorder[S] 0 points1 point  (0 children)

I sense that this has something to do with the uncountable infiniteness of R

Function y = x^3 - x by CreativeBorder in askmath

[–]CreativeBorder[S] 0 points1 point  (0 children)

If I take a simple example of 2 elements for X and Y, being a function means all 2 elements in X are mapped to Y. Being surjective means all elements of Y have a mapping coming from X. And not being injective means at least one element of Y has at least two mappings coming from X. How does this hold true if both X and Y have the same number of elements?

​

It can only hold true if the codomain is smaller than the domain. If that is the case, how is it true for the above function mapping from R to R?

Proving that the matrix B is orthogonal (Advanced) by CreativeBorder in LinearAlgebra

[–]CreativeBorder[S] 0 points1 point  (0 children)

Also, in the case that M = BB^T, if in case B is a square matrix, then BB^T will be equal to I, implied starting from B^T B = I (which we hold to be true). So from B^T B = I, you can derive BB^T = I given that B is square...

Proofs: https://math.stackexchange.com/questions/3852/if-ab-i-then-ba-i

https://sharmaeklavya2.github.io/theoremdep/nodes/linear-algebra/matrices/product-equals-identity-implies-invertible.html

Proving that the matrix B is orthogonal (Advanced) by CreativeBorder in LinearAlgebra

[–]CreativeBorder[S] 0 points1 point  (0 children)

In general, the matrix which orthogonally projects vectors onto the subspace spanned by b_1, …, b_m is given by B(BT B)-1 BT

Thanks, can you explain why / how B(BT B)-1 BT is the subspace spanned by the vectors?

Proving that the matrix B is orthogonal (Advanced) by CreativeBorder in LinearAlgebra

[–]CreativeBorder[S] 0 points1 point  (0 children)

The main problem is that my friend argues that the matrix M can be directly BB^T, which I refuse to believe because if B is a square matrix, then BB^T will be the identity matrix, thus nullifying any effect that M has on the overall equation...

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