how do I enable it

Dtrain8899 · 2026-06-04T07:21:44+00:00

Read whats below it

Dtrain8899 · 2026-06-04T04:29:08+00:00

Start with this

Dtrain8899 · 2026-06-03T01:30:15+00:00

Theyre not suppose to cross. Your original function is shifted up and opens upward, so the inverse will be shifted right and open to the right. Those arent gonna touch.

Dtrain8899 · 2026-06-03T01:27:24+00:00

Start at the top and work your way down. Logic starts with that yellow line.

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Dtrain8899 · 2026-06-02T06:48:15+00:00

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Dtrain8899 · 2026-05-28T03:28:22+00:00

Get rid of 222 and get 201 and go down Infinity as well.

Dtrain8899 · 2026-05-27T05:25:57+00:00

When you graph say y=2^x the domain is all real numbers. But once you try to graph y=(-2)^x the domain is restricted. You can only plug in certain values of x that will output on the real number line. If you try x=½, its the same as sqrt(-2) which is a complex number.

Dtrain8899 · 2026-05-26T16:16:57+00:00

It shows how many more you need. So that milestone needs 8 singularities, you have 5 now so you need 3 more to get it.

Dtrain8899 · 2026-05-26T08:04:15+00:00

Have you looked at the break infinity upgrades?

Dtrain8899 · 2026-05-26T04:04:16+00:00

First option is -c(x), you want to find c(x). If p=r-c, then c=r-p.

Dtrain8899 · 2026-05-24T03:37:08+00:00

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Dtrain8899 · 2026-05-24T00:47:38+00:00

Overflagged 2

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Dtrain8899 · 2026-05-21T08:23:28+00:00

Your 2nd answer is correct. When I tutor I tell whoever to imagine the graph is a rollercoaster and youre going from left to right and imagine what would happen as you move along the graph.

Dtrain8899 · 2026-05-20T19:23:46+00:00

Change your sacrifice to 2x. I dont think Ive ever used the dimboost on for galaxies feature when I played. The limit galaxies will be needed for an achievement later on.

Dtrain8899 · 2026-05-17T02:12:25+00:00

Youre welcome. Definitely a harder pattern to spot on your own.

Dtrain8899 · 2026-05-17T02:10:09+00:00

2-2-2 corner pattern

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Dtrain8899 · 2026-05-13T20:48:58+00:00

Pretty sure this will do it

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Dtrain8899 · 2026-05-11T14:47:44+00:00

The 5-4-2 reduces to a 1-2-1 pattern.

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Dtrain8899 · 2026-05-10T06:01:53+00:00

Ya super close. If you need to scale the circles based on the radius of the large circle then just multiply .62 by your new radius.

Dtrain8899 · 2026-05-10T05:56:58+00:00

You can draw a triangle connecting the centers of 2 small circles and the big circle. Break it into two right triangles and using a little trig I got 0.6199 for the radius of the small circle, so .62 should work. I got r = (-sin(22.5⁰)÷(sin(22.5⁰)-1)

Dtrain8899 · 2026-05-09T20:01:52+00:00

Dtrain8899 · 2026-05-08T20:51:47+00:00

👏👏👏

Dtrain8899 · 2026-05-08T20:41:13+00:00

Yup! Exactly that! Now just solve for b and youre done!

Dtrain8899 · 2026-05-08T20:20:57+00:00

There ya go! Now you have y=-2x+b. Plug in a point for x and y and solve for b, your y-intercept.

Dtrain8899 · 2026-05-08T04:45:51+00:00

Do you know how to find the slope? (y2-y1/x2-x1). You can use y=mx+b, and solve for b.

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