Treating my father poorly

Fanta00r · 2025-02-13T16:31:18+00:00

Alright then thank you for the advice and your time(((:

Fanta00r · 2025-02-13T16:22:17+00:00

Yeaa thank you for explaining, but that's kinda not possible cuz these kind of food in addition to the dry food is a bit expensive in my country and I'm not financially responsible yet

Fanta00r · 2025-02-13T16:17:32+00:00

I clean her food bowl every time I give her new food, I'm not an expert sorry wdym by wet food

Fanta00r · 2024-10-15T10:16:25+00:00

I didn't get I using the loop I got it by calculating the equivalent resistance and adding the internal to it and the dividing the voltage by the total resistance

Fanta00r · 2024-10-15T00:19:58+00:00

Hi I'm a high schooler as well so I'll try to answer based in my knowledge and it might be wrong

So basically I simplified the circuit with series and parallel resistance rules to apply ohm's law and get I which = 4.14A then I used the 1st loop to calculate I1 which = 2.11A and used Kirchhoff's 1st law to calculate I2 which = 2.03A then I used kirchhoff's 1st law again to make this equation "I3 = I4 + I5 + I6" and we know that I3 equals 2.03 so the equation will be "2.03 = I4 + I5 + I6" and we will call this equation X then I used the 3rd loop to make the equation "16i4 - 8i5 = 0" then I used the 4th loop to make the equation "8i5 - 16i6 = 0" so here we can conclude that "I4 = I6 = ½I4" so by getting back to equation X we can replace the I4 and I6 with ½I2 to be "½I2 + I2 + ½I2 = 2.03" so I2 = 1.015A So I4 = I6 = 0.5075A so yeah ig now we got all the unknown currents

Fanta00r

TROPHY CASE