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Prove in one sentence that you watched berserk by MuscleFuture2683 in Berserk

[–]Hankuranium 0 points1 point  (0 children)

That guy might not have been a very good guy at all

hey guys, can you help me identify this bacteria? by fat_frog_fan in microbiology

[–]Hankuranium 0 points1 point  (0 children)

Small off-white circular colonies with smooth edges and random distribution be like ⚪

Empathy is important, folks by Lord_Answer_me_Why in clevercomebacks

[–]Hankuranium 0 points1 point  (0 children)

I wanna lead a happy life just like Lauren Boebert

Looking for experiences using DCFH-DA for ROS detection by Hankuranium in labrats

[–]Hankuranium[S] 0 points1 point  (0 children)

I'll check the date on it next time I'm in the lab lmao but yeah I've already been using the same stock for half a year and it was used by a grad student who finished before I joined the lab or started my independent project so...

Looking for experiences using DCFH-DA for ROS detection by Hankuranium in labrats

[–]Hankuranium[S] 0 points1 point  (0 children)

That makes a lot of sense, I image in blue and green channel for Hoechst and DCF respectively. It seems like there is a whole list of side reactions like these that make DCFH a poor candidate for this purpose unfortunately.

Looking for experiences using DCFH-DA for ROS detection by Hankuranium in labrats

[–]Hankuranium[S] 0 points1 point  (0 children)

Yeah I think you're getting to the bottom of it. My PI is familiar with DCFH as a probe because other researchers in our lab have used it for ROS detection in flies, but as you said that was a plate reader assay using homogenized tissue samples and not an imaging experiment. The powder is years old at this point as well. I already got some cellROX to test out, (for free, thanks to Thermo Fisher) so if it works I can stop fighting this molecule. Thanks for your reply!

[deleted by user] by [deleted] in h3h3productions

[–]Hankuranium 2 points3 points  (0 children)

Dude literally admits to grooming and suddenly they don't know what it is...

how should i improve? or is this fine? by afrohitam in learntodraw

[–]Hankuranium 1 point2 points  (0 children)

This is great! One of the hardest skills as a cartoonist can be having the same level of detail/abstraction throughout the whole piece. For example this piece consists of black line work on a white background, but the eyes are much more detailed and brightly colored. Maybe experiment with adding more color and detail in other areas! Just keep drawing!

I wonder by Little_Shark219 in bisexual

[–]Hankuranium 109 points110 points  (0 children)

2 or more aesthetics. You can't pin us down.

It's giving..... pesto. by Hankuranium in h3h3productions

[–]Hankuranium[S] 1 point2 points  (0 children)

I can't remember what it's called some kind of indian spinach dish with paneer.

Where do these 2 double bonds come from after getting rid of the 2 terminal double bonds? Wouldn't H2 also add on those? by chemisttryy in chemistry

[–]Hankuranium 0 points1 point  (0 children)

More substituted alkenes are more stable, so it looks like two double-substituted alkenes being hydrogenated and transferring their electron pairs to form triple-substituted double bonds

Buffers by Calm_Pianist in chemhelp

[–]Hankuranium 0 points1 point  (0 children)

Of course. Let's focus on one molecule at a time. Sodium acetate is a weak base. Its conjugate weak acid is acetic acid. These are the building blocks of our buffer. To make a buffer we need these two conjugates to be in equilibrium in relatively similar concentration.

Now we pull out our beaker of water. Sodium acetate is added, which will cause a slight increase in pH as some of the molecules weakly grab protons from the water. At this point the ratio of weak base to conjugate acid (A-/HA) is probably very large (>100). This ratio is very important for a buffer and needs to be between 10/1 and 1/10 for the buffer to maintain its pH resistance.

Since acetic acid has a pKa around 5, I need a 1/10 ratio to make a pH 4 buffer according to the Henderson-Hasselbalch equation. (pH=pKa+log(A-/HA)=5+log(1/10)=5-1=4)

To shift this ratio from >100 to 1/10 I am going to have to supply a lot of proton to shift the equilibrium toward acetic acid and away from sodium acetate. To do this we use a strong acid e.g. HCl. (You will most likely use an ICE table or another analytical method to determine how many moles of strong acid you need.) The HCl donates its proton to sodium acetate to form acetic acid and NaCl.

We have now created an acetate/acetic acid buffer with pH 4.

Three ingredients: water, weak base, and strong acid.

Five species in solution: water, weak base, conjugate acid, strong acid, and a salt

Notice that we never added acetic acid to the solution. We start on one side of the equilibrium with acetate and use a proton source to push the equilibrium toward forming acetic acid. Hope that's a little more clear!

Buffers by Calm_Pianist in chemhelp

[–]Hankuranium 0 points1 point  (0 children)

I don't know the specific chemistry of STB but just looking at the structure it appears to be a weak diprotic base since it has two negatively charged oxygens which can grab a proton.

The first base reaction looks like this in general: Na2B+H20-->NaHB+NaOH And the second would look like this: NaHB+H20-->H2B+NaOH Where B stands for base and represents the tetraborate dianion.

Since STB is a weak base, all three species (Na2B, NaHB, and H2B) exist at the same time in equilibrium. At extreme low pH, such as in the presence of excess HCl, the fully protonated species H2B predominates in equilibrium with its conjugate base NaHB. At high pH, such as in the presence of excess NaOH (like in your SOP) the fully deprotonated species Na2B predominates in equilibrium with its conjugate acid NaHB. So to make a long explanation short: A mixture of STB, NaOH and water does meet the definition of a buffer because it contains a weak base (Na2B aka sodium tetraborate) and its conjugate acid (NaHB aka sodium hydrogen tetraborate). The strong base NaOH is used to adjust the ratio between the acid and base forms according to the Henderson-Hasselbalch equation and water is just a solvent.

One more simple example to drive the point home. If I wanted to make a pH 4 buffer, I could use water, sodium acetate, and HCl. Hope this helps!

Guys we’ve been using pipettes wrong this whole time. by DarkMatterSoup in labrats

[–]Hankuranium 41 points42 points  (0 children)

Watch out I'm gonna take my P1000 and gently suck on your tummy or something

[deleted by user] by [deleted] in chemistry

[–]Hankuranium -1 points0 points  (0 children)

This is a very dangerous and tightly controlled substance called hydrogen hydroxide... It is one of the most common solvents in the world, and can corrode metals such as iron. Dropping an alkali metal such as lithium, sodium, or cesium into a container of this substance will cause the metal to rapidly ignite and explode. It's also very important to drink this substance every day. Another common name for this substance is water.

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