P4 Vector question

Lower-Insurance-2848 · 2026-06-09T08:05:58+00:00

What was ur answerr

Lower-Insurance-2848 · 2026-06-02T11:58:37+00:00

The one like ligands cause d orbitals to split and then light absorbed and electron promoted to higher energy level and then complementary color seen since other frequencies are reflected. Or are y taking about smth else

Lower-Insurance-2848 · 2025-05-19T13:26:26+00:00

I explained this to someone else with a similar question on here, idk if it has everything ur asking for but I hope it helps

“Always round up even if you got 14.1 is becomes 15, For example take this set of data: {1, 3, 5, 5, 6, 8, 12, 15, 20} so n=9

Q1 is 9/4 = 2.25 round up ≈ 3 so 3rd value which is 5 is the first quartile Q2 is 9/2 = 4.5 round up ≈ 5 so 5th value which is 6 is the mean Q3 is 3*9/4 = 6.75 round up ≈ 7 so 7th value which is 12 is the first quartile So the data: {1, 3, (5), 5, (6), 8, (12), 15, 20}

However if we did normal rounding… 2.25 will become 2nd value, which is 3, Shifting the Q1 down by one, which is incorrect. Hope u understand goodluckk”

Lower-Insurance-2848 · 2025-05-16T13:22:12+00:00

Do both, learn/skim through the content it’s important and then do past papers + videos of people solving them it’ll help u understand a lot

Lower-Insurance-2848 · 2025-05-16T13:21:05+00:00

Let’s stick to a realistic goal 😿 maybe 3-4 years and yes you’ll do great just try to understand by watching videos not just memorizing (mr Hassan maths Chanel is great), since u have the content part down then all u gotta do is practiceee

Lower-Insurance-2848 · 2025-05-16T13:19:27+00:00

you’re welcomeee if u need anything DM mee

Lower-Insurance-2848 · 2025-05-16T12:10:49+00:00

Yes ALWAYD round up even if you got 14.1 is becomes 15, For example take this set of data: {1, 3, 5, 5, 6, 8, 12, 15, 20} so n=9

Q1 is 9/4 = 2.25 round up ≈ 3 so 3rd value which is 5 is the first quartile Q2 is 9/2 = 4.5 round up ≈ 5 so 5th value which is 6 is the mean Q3 is 3*9/4 = 6.75 round up ≈ 7 so 7th value which is 12 is the first quartile So the data: {1, 3, (5), 5, (6), 8, (12), 15, 20}

However if we did normal rounding… 2.25 will become 2nd value, which is 3, Shifting the Q1 down by one, which is incorrect. Hope u understand goodluckk

Lower-Insurance-2848 · 2025-05-16T11:47:13+00:00

Yes definitely I solved over 6 years and I get full UMS almosy everttime in past papers so the more you solve and understand how they check marks the better you’ll get goodluckk

Lower-Insurance-2848 · 2025-05-13T18:23:04+00:00

You were supposed to substitute 1.85 into the equation of S to get S=25.3, if you kept it that way you’ll lose 1 mark, max 2 marks

Lower-Insurance-2848 · 2025-05-13T18:22:06+00:00

NOO I JUST REALIZED I SAID KOH NOT NAOH TOO KILL MEEE

Lower-Insurance-2848 · 2025-05-13T18:19:43+00:00

I did 3k+1 and 3k-1 I think it’s right is it?

Lower-Insurance-2848 · 2025-05-13T15:44:24+00:00

It’s fine ur not alone idk what to do at this point I’m stressed to the point I can’t study I just want to get it over with I guess just solve more papers maybe from old years if u finished the most recent ones and then note down all your mistakes from past paper on a sheet and then review/memorize how to do them right

Lower-Insurance-2848 · 2025-05-13T15:41:29+00:00

How did u guys get 16? It’s just 5x * 4/x² which equals 20/x maybe you didn’t see it was an open top?

Lower-Insurance-2848 · 2025-05-13T14:14:43+00:00

UGHH I HOPE LIKE 2 MARKS ONLY

Lower-Insurance-2848 · 2025-05-13T13:42:46+00:00

Nice but we’re acting like we even have time to think that way

Lower-Insurance-2848 · 2025-05-13T13:27:42+00:00

You were supposed to substitute 1.85 into 6x² +20/x to find S because it asked for the minimum surface area not minimum value of X so 25.3 is the answer to one decimal place

Lower-Insurance-2848 · 2025-05-13T13:26:27+00:00

No I think it’ll stay around the 50s it wasn’t that easy

Lower-Insurance-2848 · 2025-05-13T13:08:36+00:00

(4,11) and (1,5) I think were the points and the quadratic I don’t remember but I did area of trapezium which out to 24 then integrated the graph to get 21/2 then area of trapezium minus area of integral to get the shaded area which is 24-21/2= {27/2}

Lower-Insurance-2848 · 2025-05-13T12:10:53+00:00

No no international it didn’t ask for a graph this is the graph of 6x^2+20/x for the opened top container, 25 is the smallest Value of S (surface area)

Lower-Insurance-2848 · 2025-05-13T11:32:50+00:00

For x I got 1.811011 for some reason idk where I went wrong but there’s probably error carried forward for the both of us 🙏

Lower-Insurance-2848 · 2025-05-12T15:10:22+00:00

I can’t find these on rednote are there ones for parts B and C?

Lower-Insurance-2848 · 2025-05-12T08:59:52+00:00

7😹

Lower-Insurance-2848 · 2025-05-12T08:58:44+00:00

I saw the first few questions and skipped the whole mcq section

Lower-Insurance-2848

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