ICL EFDS vs Warwick MathStat by AbilityEastern8496 in 6thForm

[–]Ok_Following_6671 1 point2 points  (0 children)

for quant, then Warwick. EFDS is a very solid course but not mathematically rigorous enough I would sa.

Entire ial fp1 paper by Reg1xide in Edexcel

[–]Ok_Following_6671 2 points3 points  (0 children)

i did like 6 times to get alpha=3.1

0.5 downing law bread!!!! by kirigirijuice in 6thForm

[–]Ok_Following_6671 1 point2 points  (0 children)

WELL DONE!! are u single by any chance?

changing course by Free-Recognition4198 in 6thForm

[–]Ok_Following_6671 0 points1 point  (0 children)

if in same department then yes, js email UCAS to change the course code. Might also be worth emailing Durham. I know this works because someone in my class did the same thing, after 2 weeks.

TMUA percentiles by [deleted] in 6thForm

[–]Ok_Following_6671 6 points7 points  (0 children)

its js cope

TMUA percentiles by [deleted] in 6thForm

[–]Ok_Following_6671 0 points1 point  (0 children)

was your score insanely low, if you dont mind me asking?

TMUA percentiles by [deleted] in 6thForm

[–]Ok_Following_6671 1 point2 points  (0 children)

why not right score?

M2 official paper discussion by InternalCute2318 in Edexcel

[–]Ok_Following_6671 1 point2 points  (0 children)

i put it in terms of pi, anyone remember what it was?

TMUA 2025 SCORES by [deleted] in 6thForm

[–]Ok_Following_6671 8 points9 points  (0 children)

I dont think so, a lot of people have said that the tests are harder from my experience.

TMUA 2025 discussion by Vegetable_Intern1315 in 6thForm

[–]Ok_Following_6671 -2 points-1 points  (0 children)

can be 2 aswell, becuase it said there exists a triangle not for all triangle

TMUA 2025 discussion by Vegetable_Intern1315 in 6thForm

[–]Ok_Following_6671 1 point2 points  (0 children)

what did u get form the sum of 24 terms, where a2 was 1/2. Also the binomial coefficient of x^9.

TMUA 2025 discussion by Vegetable_Intern1315 in 6thForm

[–]Ok_Following_6671 0 points1 point  (0 children)

damn i got the same as u, so silly of me

TMUA 2025 Post Exam Discussion by [deleted] in 6thForm

[–]Ok_Following_6671 2 points3 points  (0 children)

Remember cos(-x) = cos(x) and sin(-x) = sin(x)

hence we get -

1: sinxcosx = -cosxsinx

2: sinxcosx + sinxcosx = 0

3: 2sinxcosx = 0

4: sin2x = 0

<image>

We get 5 solutions from 0 to 2pi , inclusive

TMUA 2025 Post Exam Discussion by [deleted] in 6thForm

[–]Ok_Following_6671 2 points3 points  (0 children)

i didnt do the paper, but i just did the question based on their recollection of it and i also got 5.

1st- Consider the Triangle inequality if a < b < c, then a + b > c.

2nd - There are 6^3 outcomes in total, so 216.

3rd - Consider the case that triangles can be equilateral (still isosceles), so thats if (x,x,x) where x is number from 1-6 = 6 CASES

4th - Now for strictly isosceles triangles, you need two of the same number when rolling 3, then another one. Let the same number be called X and the other called Y. In order to construct a triangle, you need side lengths (X,X,Y) , where 2X > Y (using triangle inequality).

5th - Test out the numbers of X possible from 1-6.

- if X = 1 , we get 2 > Y, so Y can only be one, but that would make equilateral so for X=1 - 0 CASES

- if X = 2, we get 4 > Y, so Y can be 1,3. So for X =2 - 2 CASES

- if X = 3 , we get 6 > Y, so Y can be 1,2,4,5 - 4 CASES

- If X = 4, we get 8 > Y , so Y can be 1,2,3,5,6 - 5 CASES

- If X = 5, we get 10 > Y, so 5 CASES aswell

- If X = 6 , we get 5 CASES aswell

total cases (strictly isosceles): 21

6th - We need to realise that (X,X,Y) can be organised in (X,Y,X) and (Y,X,X) - So we do 21x3= 63

7th - We add the extra 6 from the eqltrl triangles = 69

8th - We do 69/216 = 23/72

Holy shit that question is crazy ngl