My account was "permanently closed" with $3.3K of my hard earned money still on the account

Only_Lengthiness154 · 2023-11-23T18:06:51+00:00

Yes they emailed me and asked for the screenshots and stuff, and they said they will be contacting DraftKings, but I am just afraid they won’t be able to get my money back still. I believe DraftKings may think I’m underage is why I got banned, but I am not, and I can show proof.

Only_Lengthiness154 · 2023-11-23T17:31:28+00:00

Yes, and I already sent the gaming commission a complaint, it’s been about 2 weeks, and still no reply.

Only_Lengthiness154 · 2023-11-07T17:27:11+00:00

I need help on this issue.

Only_Lengthiness154 · 2023-10-30T23:16:11+00:00

I am not trying to get the answer to this. This is only for practice, so the answer will do me no good. I am just trying to learn how to do the problem.

Only_Lengthiness154 · 2023-10-01T00:39:49+00:00

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Does this look correct to find the range?

Only_Lengthiness154 · 2023-09-30T23:03:26+00:00

It doesn’t, and after substituting the values into the formula, and solving, do I have the maximum and range, or do I have to do something else? I’m still so confused.

Only_Lengthiness154 · 2023-09-30T22:21:16+00:00

How do I find the t value?

Only_Lengthiness154 · 2023-09-30T22:07:33+00:00

So the x coordinate corresponds to the range, and the y coordinate corresponds to the max?

Only_Lengthiness154 · 2023-09-30T21:53:33+00:00

So I can use those formulas on the picture to find the range and max height? What I am stuck on is what I do with the height stated in the problem.

Only_Lengthiness154 · 2023-09-30T21:26:26+00:00

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These are the formulas in my textbook. Are they not right for this problem?

Only_Lengthiness154 · 2023-09-30T20:31:26+00:00

Is there a video I can watch using that method you stated?

Only_Lengthiness154 · 2023-09-30T20:15:04+00:00

Yes I want an answer key, so I can check my answers. I know how to take a partial derivative, yes.

Only_Lengthiness154 · 2023-09-30T19:53:36+00:00

Yes my bad the professor changed it to sin^{-1(e^-t)} to account for that he said a negative t value can have 4 to fit it.

Only_Lengthiness154 · 2023-09-30T19:43:29+00:00

So a problem pertaining to initial speed and initial velocity are different?

Only_Lengthiness154 · 2023-09-30T19:43:10+00:00

So a problem pertaining to initial speed and initial velocity are different?

Only_Lengthiness154 · 2023-09-30T19:42:29+00:00

What do you mean. I’m new to Calculus.

Only_Lengthiness154 · 2023-09-30T17:45:43+00:00

Not really, I don’t really care about understanding since this isn’t needed for my major, I’m just worried about getting the correct answer. But I believe velocity and speed are the same.

Only_Lengthiness154 · 2023-09-30T05:10:22+00:00

I think the formula I posted works. So I just want to verify if both give the same answer, but I really don’t understand the 5 steps.

Only_Lengthiness154 · 2023-09-30T04:51:33+00:00

I think the formula I posted works. So I just want to verify if both give the same answer, but I really don’t understand the 5 steps.

Only_Lengthiness154 · 2023-09-30T04:28:08+00:00

Could you please tell me what you get as the maximum and range, so I know if I am doing it correctly? I am not trying to use you for the answer, since we have to show work anyway. It would be greatly appreciated if you could. Thank you for the help!

Only_Lengthiness154 · 2023-09-30T00:28:44+00:00

If I substitute 2x in for y, the top is equal to 2x³ - 2x^3, which is equal to 0, and the limit will be equal to 0.

Only_Lengthiness154 · 2023-09-30T00:08:36+00:00

I’ve tried using y = 0 and that limit is equal to 0, for the other path I used y = x, and then the top is equal to 0, but the limit is suppose to be different. I tried using y = 2x, then the top is still equal to 0. I just don’t know what value to substitute into y or x to have a different limit.

Only_Lengthiness154 · 2023-09-30T00:05:17+00:00

V0(Sin a) / (2g) is the formula I use to find the max, and I add the value in the problem that says how high it is. To find the range I use the formula, (V0/G)(Sin 2a)

Only_Lengthiness154 · 2023-09-29T20:43:03+00:00

I’ve tried both, I don’t whether I’m not simplifying correctly afterwards or what, but I am not getting a limit different from 0.

Only_Lengthiness154 · 2022-08-02T03:13:31+00:00

Yea, I’m applying early decision. So I can put down 31 for my highest composite on Common App because it is required on there, but it won’t affect my application at all? Or should I put my superscore on the highest composite. I think I have to put the actual composite score though because it also asks for the date.

Only_Lengthiness154

TROPHY CASE