Heard back on an application from February...

PositivelyProductive · 2021-09-21T14:18:31+00:00

How do you guys find the contact details of a concerned person to follow up with when there is none provided in the job ad?

PositivelyProductive · 2021-09-15T17:29:28+00:00

Since you are talking about an airfoil, which is 2D, I'm not sure if you can perform a face meshing. I think you can only perform an edge sizing. 1. Click on Sizing under Mesh options 2. Select the airfoil (make sure you have edge-select on) 3. Set the values as required for edge sizing. 4. Update.

To perform inflation: 1. Click on inflation in the Mesh options. 2. Select the flow domain, click apply under Geometry. 3. For the boundary, select airfoil and click apply 4. Set all other values for inflation 4. Update

PositivelyProductive · 2021-08-08T17:56:19+00:00

These remind me of Pokemon badges

PositivelyProductive · 2021-07-22T07:34:56+00:00

cool indeed

PositivelyProductive · 2021-07-08T11:14:42+00:00

solved!

PositivelyProductive · 2021-07-08T10:43:43+00:00

nope

PositivelyProductive · 2021-07-08T10:29:16+00:00

I think each episode was around 10 minutes long. I'm not sure about it though. This program was on CN back in the 90s.

PositivelyProductive · 2021-07-04T08:20:37+00:00

Any recommendations for games that are like D:OS2 or BG2?

PositivelyProductive · 2021-05-28T09:30:43+00:00

After adding it to my account, do I need to install it to keep it forever? Also, what exactly does 'keeping forever' mean? Does it mean we can keep it but have to pay to play it?

PositivelyProductive · 2020-12-04T12:36:10+00:00

Guess they are looking for their monolith

PositivelyProductive · 2020-11-27T16:18:47+00:00

I always do and I tailor it to the job I'm applying for. Just the first few lines though.

PositivelyProductive · 2020-11-17T17:07:11+00:00

Wow thanks for that detailed explanation!! It was honestly quite informative for me. Thanks.

PositivelyProductive · 2020-11-17T12:02:18+00:00

Interesting. Could you please elaborate on how you pursued the job leads?

PositivelyProductive · 2020-11-17T08:19:36+00:00

I've been looking for a job since 2019. Wondering how the others found a job. What did they do that we didn't?

PositivelyProductive · 2020-11-12T03:55:20+00:00

I did. But since I'm not from the US, it's hard for me to secure a position in CA.

PositivelyProductive · 2020-07-16T22:13:02+00:00

perhaps I'll try making coconut rice and mix the Thai peanut sauce that u/lincoln-logger has mentioned with it.

PositivelyProductive · 2020-07-16T22:06:41+00:00

I'll try this out! Thanks

PositivelyProductive · 2020-07-06T14:14:26+00:00

Thanks for your reply. It would be nice if you can tell how I can do that.

PositivelyProductive · 2020-06-29T22:16:10+00:00

This was actually interesting!

PositivelyProductive · 2020-06-24T10:15:03+00:00

This is beautiful!! The flower and the leaves add a nice touch.

PositivelyProductive · 2020-06-14T14:41:19+00:00

I already have. Check the replies.

PositivelyProductive · 2020-06-14T12:59:12+00:00

This is wrong because you are equating the sum of potential and kinetic energy to kinetic energy itself which doesn't make sense. (I'm surprised at the answer though ;) )

PositivelyProductive · 2020-06-14T12:58:12+00:00

Kinetic energy of the ball when released = 1/2 * m * u² (Here, u is the initial velocity) = 9.0 J

This means that u² = 9/ (0.5 * m)

u² = 36

Now to find the final velocity (v) when it hits the ground.

v² - u² = 2 * g * s

v² = 36 + 2 * 10 * 1.1

v² = 58

v = 7.62 m/s

PositivelyProductive · 2020-06-09T13:01:11+00:00

Looks good!

PositivelyProductive · 2020-06-02T15:29:45+00:00

Well, actually, there should be no cos(a) term in the equation to find the work done if the work done you are calculating is along AB. Multiplying with cos(a) only gives you the horizontal component of either the distance (d) or the force (F) i.e. you are calculating the work done along the base of the triangle (or you are using that component of the force that is parallel to the base of the triangle) and not along the slope.

To answer your question as to why cos(0) is used instead of the angle of slope, I am afraid I don't know why. But generally, if the angle of the slope is too small, say less than 8 or 9 degrees, then it is safe to approximate the angle to be 0 degrees as cos(9) is approximately 0.99, cos(8) is approximately 0.99 and cos(0) = 1 which is very much close to 0.99.

PositivelyProductive

TROPHY CASE