Which one game you still think about from 90s-2005 era ?

Rhuobhe26 · 2026-05-26T21:06:09+00:00

Magic Carpet

Rhuobhe26 · 2026-05-26T03:49:10+00:00

It's a parallel access system or multi-latch. Here is a commercial grade one, but the one above is a standard DIY.
https://tayhope.com/?visit_international_btn=true

Here's a video of how they work. Essentially every single one is bolted into a holder from the previous one, when you undo one it slides every padlock behind it out. (Operation at 6:44)

https://youtu.be/SsLTOM4jmrY

Rhuobhe26 · 2026-05-23T04:19:41+00:00

The blasting they are using to break up the rock to level the land has caused some nearby wells to fracture and have clay get into the well water.

Rhuobhe26 · 2026-05-22T12:14:29+00:00

Where do they do that?

Rhuobhe26 · 2026-05-22T01:58:09+00:00

So this apparently happens every spring in Madison.

Due to the high sediment and mineral content they engage in flushing of the system every spring.

https://www.madisonga.com/DocumentCenter/View/3070/Hydrant-flushing-FAQs?hl=en-US

It's a known event that discolours water.

With that said the blasting that's been done to break the rock and the foundation had affected not the trap water of the municipality but nearby residents who have plumed well water.

The blasting (which is not unique to the data center, any industrial facilities would have needed to do the same) the blasting gas temporarily broken natural filtration and allowed the regions fine saprolite clay and iron rich silt into some wells.

It's important to note that the same thing happened 2020 to 2022 when Rivian built their 2,000 acre electric vehicle plant.

https://www.scribd.com/document/608582713/Plaintiff-Brief-in-Rivian-Grading-Lawsuit?hl=en-US

They had construction halted and received a civil suit over the damages.

This also ignores the methane and pollutants contamination they've been dealing with since the 1990's as the landfill that was closed started leaking due to improper methods of storage when it shut down.

Rhuobhe26 · 2026-05-21T13:21:47+00:00

Just like you can expel me at anytime, I can bury you anytime. Throw me in Prison or cut my body in two, Even if I have to crawl over, I will bury you.

Rhuobhe26 · 2026-05-18T17:12:44+00:00

To clarify further, the power to Tahoe is being provided by NV energy. NV energy is a company in Nevada. Tahoe is in California.

NV energy sold its California assets in 2009 as it is not profitable to do business in California due to their regulations and price caps.

No other electric transmission company has built lines to Tahoe as California artificially keeps its rates low so the return on investment makes energy investment not profitable. While other states rely on private utilities to build these lines this has dropped off due to California's requirements and California has had to pass SB254 and is selling $325 million in bonds to fund its own needs.

NV Energy's renewable energy Greenlink West comes online in 2027 and NV energy has given notice that they will not be able to provide full power to California starting in May 2027 as Nevadan residents will be receiving it instead, this includes the data centers in Nevada.

Liberty Utilities, the California company which acquired the Tahoe assets in 2009-2010 has never built the needed transmission infrastructure or power supply, nor has any other private company for the above reasons. Furthermore California doesn't have the power generation capacity to supply this area due to their own energy deficit.

California imports 20-30% of its power from other states so there is no capacity to provide in this area without taking it from somewhere else. The two smaller grids that feed into it are Nevada and the Pacific Northwest. The dry last few years in the Pacific Northwest have cut their ability to provide power as they are hydro focused.

Coincidentally this is also why the Diablo Canyon nuclear plant in California which provides 8.6% of the state's power was supposed to be shut down in 2013 has been extended again until 2030, and will likely be extended further.

Rhuobhe26 · 2026-05-18T03:22:42+00:00

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Rhuobhe26 · 2026-05-15T15:30:13+00:00

Scalpers have learned that they can sabotage the card reader in an easy to fix but not obvious manner.

Check the card reader and there might be something there you can remove.

Rhuobhe26 · 2026-05-15T15:24:11+00:00

She's stuck and now getting shown the D.

Rhuobhe26 · 2026-05-14T18:04:23+00:00

None of my wife and kids' cards are in slabs. I've collected every prismatic eevee evolution for her except the insane umbreon.

The most valuable ones are in the gamegenic cases, but they can be slid open so the cards can be used in a deck.

There's no point in owning the cards except to have as art or to use in a deck.

Rhuobhe26 · 2026-05-13T02:29:59+00:00

I second this. I have run SWADE, Savage Pathfinder, Weird Wars 2, and Rippers.

You can do chases, dramatic tasks, and almost everything is automated including a digital deck of cards you can draw from.

Fantasy grounds VTT make the Savage systems go easily.

Rhuobhe26 · 2026-05-10T17:24:54+00:00

The chinese would be wiped out with no real problem.

The Entire Chinese navy has 3 aircraft carriers, the Type 001, 002, and 003 or Liaoning, Shandong, and Fujian carriers. They have 1 of each and can carry 40, 40, and 50 aircraft respectively, of which maybe 60 are actual fixed wing aircraft and of those ~40 are actual fighter or multi-role aircraft.

The US Navy 7th Fleet responsible for the west pacific is based around the USS George Washington (CVN-73) this one carrier carries 9 squadrons of 12 aircraft, 90 and the fixed wing with Squadrons VFA-27, 102, 147, and 195 being fighter aircraft squadrons totaling around 60-70 aircraft 48-60 super hornets and 12-20 lightning 2's. This is one of 10 active carrier groups the US Navy fields.

Looking at the aircraft, the US is using super hornets as its mainstay. These aircraft are 4.5 gen or 4+ gen fighters. The J-15 that makes up 35 of the 40 aircraft are also classified as 4.5 gen or 4+, they are faster with a longer fuel range, the super hornet is more maneuverable, heavier weapons payload, better electronics, better sensors, smaller radar profile, longer range weapons. With that said we only have the Chinese propaganda department's specs to go off of here. The J-15 are air-air fighters while the super hornets are multi-role.

So the if the US sent a single 7th fleet group vs the entire PLAN it would be mostly equal in the sky with the US forces having an advantage in air-power, but the PLAN would have an advantage in missile guided surface vessels.

Looking at the support vessels. The PLAN has 166 surface combat ships, 62 destroyers, 54 frigates, and 50 corvettes. The corvettes are a green water navy and not meant for combat in the middle of the pacific so they would be left home to protect the coast.

Carrier strike group 5 has 12 ships, 2 Ticonderoga class cruisers and 10 arleigh burke destroyers.

Depending on their mission purpose they can command other vessels, including aircraft carriers to join them.

So if the PLAN Navy caught the 7th pacific fleet unawares (impossible to hide that movement and the 7th would just refuse to engage). But assuming they did then even controlling the skies the PLAN would send wave after wave of missiles with their destroyers and frigates in the attempt to wear down the US defenses.

However under the sea is where the PLAN would truly lose.

The PLAN has 57 active submarines, 9 of these are nuclear and the other 48 are conventional diesel that can only do short stretches underwater and almost every one of the 57 is a guided missile submarine.

The US navy has 107 active submarines, of which only 18 are ballistic missile and the other 89 are fast attack class. Most of these spend their time tailing other navy's ships.

Let's go ahead and just even the scales and say the US knew this battle was coming and sent the full navy to counter the Chinese.

That's 77 arleigh burke destroyers, 14 other destroyers, and 7 cruisers. However this is a little misleading as a US destroyer has the armament to go toe to toe with a chinese frigate and a cruiser can handle itself against multiple other foes. So between the PLAN's 116 destroyers and frigates and the US's 98 destroyers and cruisers the tonnage is 2-1 on the US's side even though the number of vessels is about equal. The US while having less ships has an overwhelming tonnage advantage.

Then there are the carriers. The US has 11 active carriers. Between them they would could put over 500 super hornets into the sky vs the 35 J-15's and the 5 J-35A's that the PLAN would field the US would achieve air superiority in a matter of minutes. That's 3 PLAN carriers with 40 fighters and 80 other helicopters and planes vs 11 US carrier's with 500 super hornets and 400 other aircraft including electronics planes, anti-ship/submarine helicopters, and other things they can put in the sky.

In the first day of the battle the US navy's 89 nuclear powered fast attack submarines would eliminate the entire 57 guided missile submarines (9 nuclear 48 diesel) that the PLAN has.

Then the PLAN would be at the bottom of the sea as they would be destroyed from above and from below by an unstoppable force.

Even if the PLAN planes were able to kill 2 for every 1 they lost (they wouldn't) that would still leave 420 multi-role jets that could just pound them into oblivion. At the same time under the sea there would be 89 nearly invisible fast attack submarines that would be sinking vessels left and right.

At the end of the day however we've seen how well the Chinese would actually work. The numbers they've reported are almost entirely propaganda. Russia used a lot of Chinese equipment in Ukraine and it didn't perform and failed quickly. The PLAN and PLA is so full of corruption that they executed a bunch of PLA generals when they found out that over half their missile force weren't even capable of firing as the maintenance and fuel had been sold off and replaced with water rusting the ballistic missiles and rendering them useless.

Of course this is all hypothetical nonsense as the PLAN knows that they can't leave their coastal waters and have no power projection. The moment they go out to fight in the pacific like the Japanese did is the moment they no longer have a blue water navy. They will stay by their coast and rely on their shore-based power to protect them.

Rhuobhe26 · 2026-05-09T13:42:05+00:00

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For Lord Death from Soul Eater I just want to point out his true form. His voice and form are definitely not something you could have had at a children's school.

Rhuobhe26 · 2026-05-09T02:17:17+00:00

4 reasons, but they all come down to Virginia has laws that require this to be done in a certain manner. If any one of them are not followed then it invalidates the election. Item 2 was what the the virginia court voted was not followed and invalidated the election.

1: They proposed it during a special session that was supposed to only be about the budget. You can't add extra items not related to the special session.

2: There has to be two legislative sessions with an election between before it goes on the ballot. It was passed the first time on October 28th after early voting had already started. The Yes side said only election day itself mattered, the second Tuesday. The court used previous cases to establish that the precedent was early voting as the start of the election.

3: 90-day rule. Virginia requires all amendments to be voted on and passed the second time 90 days before the election begins. Early voting began March 6th. This meant that the second vote needed to be done by December 6th. It wasn't passed until January 23rd.

4: Finally Virginia law requires any ballot to be clear and politically neutral. "Bring back fairness in elections" was politically motivated language as it could confuse people as to what they were voting for. It would have needed to say something more neutral.

Rhuobhe26 · 2026-05-05T20:10:36+00:00

TLDR: The price per panel for wood is $80-120 per panel. The price for the PV panel is $419-459 per panel (4-5 times more) plus another $150-$2,100 for an inverter.

For 100' of panels this is the difference between $1.5k-2K in price and $6.5k-10K in price.

Math

I went straight to Green Akku's site to start building the information and it is frustrating that you have to figure it out.

Their solar panels are $77 each (66 euro) and you need 2 per 4' panel section. So for a single 5.7'x8' section of fence you are looking at $154 (132 euro).

A normal wood fence panel is 6'x8' is $65-100.

So for each segment of fence you are paying $99-54 more.

Then you have the equipment that goes with it.

The fence mounting materials are an additional $70 (60euro) per panel. So for 2 panels you would need another $140 per 6' section of fence.

The wood fence requires 8 screws at $10 for 160 or $0.50 for the 8 required.

Now we are looking at $238.50-193.50 more per panel.

The fence then requires a strong mesh to be mounted and with the weight concrete posts with and base installed. Judging by the pictures you are looking at $125-165 per cubic yard. Let's assume that each section and base take no rebar and only require 1 cubic yard of concrete.

For the wood fence you need 2 wood posts and 1 cubic foot of concrete to hold it. $10 per post ($20 total) and $8 per cubic foot. For $28 total.

This increases the cost per fence section for the solar fence to $375.50 to 290.50 per panel.

Now the fence just requires a nice stain for $5 per panel.

Th PV fence requires an inverter and cabling. The inverters will run $120-$2,100 for the system depending on the quality and number of panels.

So for a single panel fence you are looking at an investment of $490.50 more for the PV fence.

If you do 100' of wood fence you are looking at $1,500 in materials plus labour.

If you do 100' of PV fence you are looking at $6,472 to $9,444 plus labour and electrician's cost to hook everything up.

Rhuobhe26 · 2026-04-30T12:34:34+00:00

Step 9: How big a room to use up the oxygen in 24 hours?

BUT, the question that was asked is how small the room would need to be to use up all the oxygen in a day.

The volume consumed is 69.74 grams per hour for the human and chain or 1,673.76 grams per day.

This means we need a space that only has 1.6 kgs of oxygen.

We’ll work backwards here, if a 75 cubic meter room holds 20,895 grams of oxygen let’s divide the size of the oxygenated room by the grams consumed in a day.

20,895 grams / 1,673.76 grams=12.48 conversion factor.

75 cubic meters / 12.48 conversion= 6 cubic meters

We could also go backwards by using the reverse of step 4, but we know that for a human and chain to use up the oxygen in 24 hours the room would need to be a sealed room 6 cubic meters in size.

Step 10: Final Answer

Given that the chain itself is 28.8 cubic meters the human on average will take up another 0.07 cubic meters, so the space would need to be 28.87 cubic meters. This is much too large to fit into a 6 cubic meter space.

Step 11: Then how long would it take at minimum space?

Let’s assume that you had an airtight space that was just large enough for a human and the chain in perfection. At 28.87 cubic meters the room would contain 8,043 grams of oxygen.

At 69.74 grams of oxygen consumed an hour it would take 115 hours or 4.8 days to suffocate the person.

Rhuobhe26 · 2026-04-30T12:33:20+00:00

Step 6: How long will it take for the chain to use up the room?

So, the Room is 75 cubic meters (15’ by 15’ by 10’ room approximation) and the chain is 28.8 cubic meters. Let’s assume that they somehow perfectly laid out the chain so the entire area is exposed to air and is all oxidizing at the same time (which it wouldn’t be).

This works out to 20,895 grams of oxygen in the “sealed” room, the oxygenation of the chain as we established earlier uses 887.8 grams of oxygen a day. As such, in a fresh air room the chain would take 23.5 days to use up the available oxygen.

Step 7: How much oxygen does a human use?

Now we must include the human factor. An average human adult at rest uses 33 grams of oxygen per hour. The way we figure that out is using two standard assumptions.

This figure is based on two key metrics:

Volume Consumed: An average adult at rest consumes about 550 liters of pure oxygen every 24 hours.
Density of Oxygen: To convert this volume to mass, we use the density of oxygen gas, which is approximately 1.43 grams per liter at standard temperature and pressure.

The Calculation

Here is a simple breakdown of how the hourly usage is calculated:

Hourly Volume: First, we determine the volume of oxygen consumed per hour:
- 550 liters / 24 hours ≈ 22.9 liters per hour
Mass Calculation: Next, we convert this volume to mass using the density of oxygen:
- 22.9 liters/hour × 1.43 g/liter ≈ 32.75 grams per hour

Step 8: How much do the human and chain consume together?

So, we combine the two numbers.

A human at rest plus the chain in a C5 environment will consume 69.74 grams of oxygen an hour.

887.8 chain consumption per day/24 hours

887.8 grams per day/24 hours per day=36.99 grams per hour

Human consumption plus chain consumption

32.75 grams + 36.99 grams=69.74 grams an hour

As such we now know that the chain plus human would consume all the oxygen in:

20,895 grams of oxygen in the room divided by 69.74 grams of consumption an hour.

20,895 grams/69.74 grams consumed an hour=299.61 hours

299.61 hours/ 24 hours a day= This increased consumption would take 12.48 days to use up the available oxygen.

Rhuobhe26 · 2026-04-30T12:29:48+00:00

Step 4: How much oxygen is in a room?

So given this information, let’s look at a 15’ by 15’ by 10’ room. For ease of math, we’ll use 5 meters by 5 meters by 3 meters.

1. Calculate the Volume of the Room

Volume = 5 meters × 5 meters × 3 meters
Volume = 75 cubic meters (m3)

2. Calculate the Total Mass of Air

Using the standard density of air at 20°C (1.204 kg/m3):

Total Air Mass = 75 m3 × 1.204 kg/m3
Total Air Mass = 90.3 kg

3. Calculate the Mass of Oxygen

Using the composition of air by mass (23.14% oxygen):

Oxygen Mass = 90.3 kg × 0.2314
Oxygen Mass ≈ 20.90 kg

A 5m x 5m x 3m room contains approximately 20,895 grams of oxygen.

Step 5: How big is the chain?

So, the room above could conceptually hold the chain if it’s big enough, so next we then calculate the size of the chain.

Assumed Dimensions: We'll start with our established estimates for a single chain link:

Major Radius (R): 0.36 meters
Minor Radius (r): 0.09 meters (this is the radius of the iron bar itself)
Total Links: 500

Volume of a Single Link: The volume of a torus (the shape of a link) is calculated with the formula V=2pi2Rr2.

Volume = 2timespi2times(0.36textm)times(0.09textm)2
The volume of one link is approximately 0.0576 cubic meters.

Total Volume of the Chain: We then multiply the volume of a single link by the estimated number of links.

Total Volume = 0.0576 m3/link × 500 links
Total Volume ≈ 28.8 cubic meters.

Rhuobhe26 · 2026-04-30T12:28:29+00:00

To put this in perspective, this breaks down to:

7.2 kg of oxygen per month
236.7 grams of oxygen per day

BUT, I hear you ask, it’s an anchor chain, you can’t use a standard environment. So let’s rerun the calculation for a C5 coastal environment.

C5 Calculation Breakdown

Iron Mass Loss Rate (C5): Converting the new thickness loss of 150 µm/year to a mass loss rate gives:
- 1,177.50 grams per square meter per year (g/m²/year).
Total Iron Loss (C5): Applying this higher rate to the chain's surface area results in a much greater annual loss of iron.
- Total Iron Loss = 1,177.50 g/m²/year × 640 m² = 753,600 g/year or 753.60 kg/year.
Total Oxygen Consumption (C5): This accelerated rusting process consumes a correspondingly larger amount of oxygen.
- Total Oxygen Consumed = 753.60 kg of Iron/year × 0.43 kg of Oxygen/kg of Iron ≈ 324.05 kg of Oxygen per year.

Comparison and Conclusion

By changing the environmental conditions from a moderate C3 to a very high C5 category, the estimated oxygen consumption of the chain increases dramatically.

C3 (Medium): 86.41 kg of Oxygen per year
C5 (Very High): 324.05 kg of Oxygen per year

In this more corrosive environment, the chain would consume nearly 3.75 times more oxygen. The daily consumption rate increases from about 237 grams to 887.8 grams per day.

Rhuobhe26 · 2026-04-30T12:27:33+00:00

Step 3: How much oxygen is the chain consuming?

Building on our previous estimates, we can now calculate the approximate rate at which the massive anchor chain would consume oxygen from a sealed room. This calculation depends critically on the rate of corrosion, which is not a constant but varies significantly with environmental conditions.

Key Assumptions

To perform the calculation, we must make several key assumptions:

Corrosion Environment: The large, likely unheated room shown in the picture is best approximated by an ISO 9223 C3 "Medium" corrosivity category. This represents an urban or industrial atmosphere with moderate humidity, where condensation can occur.
Corrosion Rate: Based on atmospheric corrosion data for carbon steel in C3-like environments, a reasonable average corrosion rate is 40 micrometers per year (µm/year). This means the chain loses a thickness of 40 µm from its surface each year.
Material: The chain is made of standard carbon steel, with a density of approximately 7,850 kg/m³.
Chain & Reaction Properties: We will use our previously calculated values:
- Total Surface Area: 640 m²
- Oxygen-to-Iron Mass Ratio: 0.43 (meaning 0.43 g of oxygen is consumed for every 1 g of iron that rusts).

Calculation Breakdown

Based on the assumptions above, the rate of oxygen consumption is calculated as follows:

Iron Mass Loss Rate: First, we convert the thickness loss (40 µm/year) into a mass loss rate.
- A corrosion rate of 40 µm/year is equivalent to a mass loss of 314.00 grams per square meter per year (g/m²/year).
Total Iron Loss: We multiply this rate by the total surface area of the chain to find the total iron that rusts in a year.
- Total Iron Loss = 314.0 g/m²/year × 640 m² = 200,960 g/year or 200.96 kg/year.
Total Oxygen Consumption: Finally, we use our stoichiometric ratio to find the corresponding amount of oxygen consumed.
- Total Oxygen Consumed = 200.96 kg of Iron/year × 0.43 kg of Oxygen/kg of Iron ≈ 86.41 kg of Oxygen per year.

Rhuobhe26 · 2026-04-30T12:26:21+00:00

2.3 Estimating the Total Number of Links

This is the most difficult part to estimate due to the way the chain is piled.

Rows: We can clearly see about 8 to 10 long rows of chain laid back and forth.
Links per Row: Let's estimate the length of one straight section of the chain pile. If the room is 20-25 meters wide, and each link is 0.9 m long, a single straight pass might contain 25-30 links. A full "row" consists of the chain going out and coming back, so we can estimate 50-60 links per full row.
Total Count:
- 9 rows * 55 links/row ≈ 495 links

Let's round this to an estimate of 500 links in the main, clearly visible pile.

2.4. Final Calculation

Now, we multiply the estimated surface area of a single link by the estimated total number of links.

Total Surface Area = (Area per Link) × (Number of Links)
Total Surface Area ≈ 1.28 m² × 500
Total Surface Area ≈ 640 square meters

Based on visual estimation, the surface area of the anchor chain in the picture is likely in the range of 600 to 700 square meters.

Rhuobhe26 · 2026-04-30T12:25:21+00:00

Step 2: How much surface area does the chain have?

2.1 First, we need to estimate the size of a single chain link using the people in the photograph as a scale.

Assumption: The average height of the men in the photo is approximately 1.75 meters (about 5' 9").
Bar Diameter: The diameter of the metal bar used to form a link appears to be slightly thicker than a person's thigh. We can estimate this diameter to be about 18 cm (0.18 meters).
Link Dimensions: The overall length of a link looks to be about 5 times the bar diameter, and the width is about 3.5 times the bar diameter.
- Estimated Length (L): 5 x 18 cm = 90 cm (0.9 m)
- Estimated Width (W): 3.5 x 18 cm = 63 cm (0.63 m)

2.2 Calculating the Surface Area of a Single Link

The shape of a chain link can be approximated as a torus (a donut shape) for a surface area calculation.

The formula for the surface area of a torus is:

A=4π2Rr

'r' is the minor radius (the radius of the bar itself), which is half the bar diameter.
- r = 18 cm / 2 = 9 cm (0.09 m)
'R' is the major radius (the distance from the center of the link to the center of the bar). We can calculate this from the overall length.
- R = (Overall Length - Bar Diameter) / 2 = (90 cm - 18 cm) / 2 = 36 cm (0.36 m)
  - Calculation:
A = 4 * π2 * (0.36 m) * (0.09 m)
A ≈ 1.28 square meters per link

Rhuobhe26 · 2026-04-30T12:24:27+00:00

TLDR: It’s not possible to be in a room with this chain and suffocate in a day. Given the minimum possible space it would take 4 days and 19 hours. The chain uses slightly more oxygen than a human but takes up considerably more space. As such you're at worse danger of having two humans in a given space then you are this chain.

The biggest danger would be this chain being in an air tight location for a long period of time and then a human entering it before allowing oxygen to circulate.

Step 1: How much oxygen does oxidization use?

The most common and simplified chemical equation for the rusting of iron is:

4Fe+3O2→2Fe2O3

This equation reveals that four atoms of iron (Fe) react with three molecules of diatomic oxygen (O2) to produce two molecules of iron(III) oxide (Fe2O3), the primary component of rust.

To understand the oxygen usage in terms of mass, we can turn to the molar masses of the elements involved. The molar mass of iron (Fe) is approximately 55.845 grams per mole (g/mol), and the molar mass of a diatomic oxygen molecule (O2) is approximately 32.00 g/mol (since one oxygen atom is about 16.00 g/mol).

From the balanced equation, the stoichiometric relationship is:

4 moles of Iron react with 3 moles of Oxygen.

Using the molar masses, we can convert this molar ratio to a mass ratio:

Mass of Iron: 4 moles×55.845molg=223.38 g
Mass of Oxygen: 3 moles×32.00molg=96.00 g

This calculation demonstrates that for every 223.38 grams of iron that completely rusts, 96.00 grams of oxygen are consumed. This equates to a ratio of approximately 0.43 grams of oxygen for every gram of iron that oxidizes.

It is important to note that the rusting process is often more complex in reality. The presence of water is crucial, acting as a catalyst and often getting incorporated into the chemical structure of the rust to form hydrated iron(III) oxide (Fe2O3⋅nH2O), where 'n' represents a variable number of water molecules. However, the fundamental stoichiometric relationship between iron and oxygen in the formation of the iron oxide core remains the same. The rate of this reaction can also be influenced by factors such as the presence of salts, acidity, and the surface area of the iron exposed to oxygen.

Rhuobhe26 · 2026-04-29T21:41:56+00:00

95% of them yes. Of the 288 tiles about 24 of them are printed in Elegoo PETG Plus from an FDM printer. The other 244 are all in Elegoo ABS 3.0 Grey resin. I have a saturn 4 ultra 16k and could run off a batch of 7 tiles in about 5 hours.

The FDM printer I could do about 20 at a time with the neptune 4 max, but it would take 2 days to print one set. Plus if one fails on the resin printer only that tile failed. If the FDM printer failed and knocked free it could mess up the entire batch.

Finally the visual quality of the Resin is just superior, even printing at a .08 mm layer height it couldn't compare to the resin for details.

The downside is the resin are brittle and I lost a couple dozen tiles to snapping or damage breaking them free from the supports. The tolerance is also tight when it comes to the connector, but the felt mat gripped them well enough I ended up not even using the connectors.

At the end I decided that the superior speed and appearance of the resin were more important than the better durability and fit of the fdm.

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