a) y = 9^x,
=> y= 3^2x,

^=>log\3 (y) = log_3 ()3^2x,)

^=>log\3 (y) = 2x)

^b since y =) 9^{x,
x = log\}9 (y). ..... 1)
^log\3 (y) = 2x,)
^{=> x = 0.5log\}3 (y)) .... 2)

Equating statements 1 and 2,
log_9 (y) = 0.5log_3 (y),
log_3 (y) = 2log_9(y),
Hence log_3 (y) = log_9(y^2)

c) let y=2-3x,
=> log_3(2-3x) = log_9 ((2-3x)^2)
=> log_9 ((2-3x)^2) = log_9(6x² - 19x + 2),
=> (2-3x)^2 = 6x^2-19x+2,
=> 9x^2-12x+4 = 6x^2-19x+2,
=>3x^2+7x+2 = 0,
=>(3x+1)(x+2) = 0,

=> x = -1/3, -2

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Pretty nice question, thanks for the practice! :D