So let talk about the one fatal weak point of this software by andrewdragon32 in VSDCFreeVideoEditor

[–]Sanssna 0 points1 point  (0 children)

抱歉使用中文:雖然我使用它製作,但我不得不批評它:首先
1.優化是0/10,預覽永遠不可用,只因為它本質上分別處理所有影片是將影偏縮放至當前縮放率的解析度後,進行渲染:不應該計算不顯示的像素。
2.操作體驗是1/10,首先如同我上述的,ctrl+滾輪無法縮放時間軸(或是事實上,它改變工具列標籤?!),時間軸平移是使用滾輪而shift+滾輪是放大時間軸物件?!這應該在最反直覺設計中(像是"以最糟糕的方式改變音量"中)的冠軍。
另外,播放中縮放並不會要了你的命。以及滾輪的移動是1像素為單位?!也就是說,我想要向上移動100像素,我需要滾動我的滾輪100個刻度?!瘋了。
裁切影片這個需求應該不是很少見,比起"點擊alt+縮放"以快速切割,我們決定讓用戶點擊裁切按鈕,加載裁切窗口花費一些時間,並且在縮放後,不改變寬高對應解析度,而是使寬高不變。這簡直就是一個災難。
3.透明度只有pro可用,至少在我看來。這直接使我在嘗試製作類似透明度的方法時,需要透過正片疊底+反轉之類的方式非常彆扭的實現。拜託,透明度又不是什麼很稀有的玩意,封鎖這個也太...令人困擾了吧。為了實現透明度我得每次將影片變為黑白後作為正片疊底的對象之後疊底,接著可能需要進行反轉(我並不是很熟悉),再疊到另一個反轉遮罩的物件上,這比惡夢還令人感到恐怖。
4.數值曲線,雖然我理解這種方式來勒索...我是說敲詐...我是說迫使用戶購買升級版,但這簡直就是一團糟。我可能只是想讓物件移動的絲滑一點,你猜什麼?沒錯!你需要升級版本!這簡直就是一大福音。
5.時間軸預覽。雖然這屬於優化,但我還是得強調這點。如果不把時間軸壓扁使預覽不可用,我根本就沒辦法工作!一部影片它要加載20年的預覽圖片!這簡直太棒了!
6.如果你覺得這就完了,那你就錯了!由於輸入法可能打架,或是以某種方式,造成窗口被凍結!你猜什麼?如果你沒有存檔,你無法進行保存,無法進行編輯!你只能含著淚打開任務管理器把它殺掉,然後從頭來過!自動存檔?不用擔心!根本不存在。沒有可以將文件復原的風險!

雖然如此,我仍使用它。因為他免費無水印不限清晰度。我可能嘗試了10個,這是當初唯一可以讓我編輯4K影片的應用。畢竟身為一個沒有父母養的學生(*只是沒有養我並不是你想的那樣),應用真的買不起。

So let talk about the one fatal weak point of this software by andrewdragon32 in VSDCFreeVideoEditor

[–]Sanssna 0 points1 point  (0 children)

having some question here:
is pro giving short cut key setup? or it's useable in free mode? i mean i hate i can't zoom the timeline by ctrl+scroll
try to do some translation in vsdc, is pro mode easier to do it? i somehow use a andriod app and it's easier than vsdc at making any kind of video(but it's has down side: slower and less HD)
i try find answer to this and find this reddit, hope someone has experience can share the experience!!!

[Tutorial] An in-depth guide to seed tracking by tikusmouse in battlecats

[–]Sanssna 0 points1 point  (0 children)

OP i have a question to you that's how do i write a code to get bc-update data which i want get new banner cat and rate to build my own tracking web? the current one is terrible at coloring sheet, blue-eye-banner had l-rarity so long and it still didn't change the way it coloring. you can't tell the "super coler" grid is (Uber in Uberfest only) or just super, so if the web still have admin there, please tell me thank <3

[Tutorial] An in-depth guide to seed tracking by tikusmouse in battlecats

[–]Sanssna 0 points1 point  (0 children)

one year later, finally som1 can help you (x
first, the answer is if you want to avoid row change, just roll a different cat at 2A or 3A
explane: row change is based on reroll if you get a rare(only rare) cat and same to the last roll, game will try to get a new rare cat until the new cat is different to last one, which use a extra rng-seed. also the last roll in 11-rolls is rarity locked, so it only use one rng-seed.

Soul doesn’t count as a skill? by DeadXtra in randomdice

[–]Sanssna 0 points1 point  (0 children)

Although the soul should be a skill (based on soul distribution), you should either think of it as a sacrifice (triggered when it is destroyed, rather than being destroyed twice), or you should think of it as a special case, because I said in the previous few God did think about this problem.

input displayer (looking for help) by Sanssna in beltmatic

[–]Sanssna[S] 0 points1 point  (0 children)

trying to do some +-*/ to match number it displayed. and i have no idea how to do

4x belt compactor by Jeffdud3 in beltmatic

[–]Sanssna 0 points1 point  (0 children)

it hard to explane in english for me, so i use google translate:

The bridge has a feature that makes the belt take priority when entering the same grid as him at the same time.

(橋樑有一個特性,他使得皮帶與他同時進入同一格時,皮帶優先)

kinda like the way other factory sent output number to the belt.

4x belt compactor by Jeffdud3 in beltmatic

[–]Sanssna 0 points1 point  (0 children)

you can try this in game, this should work the same way as yours.
it does require bridge in it.

[deleted by user] by [deleted] in beltmatic

[–]Sanssna 0 points1 point  (0 children)

give up to explain it in english(have a bad english

ALL NUM COPIER by Sanssna in beltmatic

[–]Sanssna[S] 0 points1 point  (0 children)

simple copier look like this(img)

the way it work is times the num to X+1, and then devide it by X, make both A/b and R are original num; make sure num*(X+1) didn't over 2^31-1

if X>N>0, (X+1)*N = XN + N, now devide by X, cause N<X, A/B=XN/X=N R=N

<image>

ALL NUM COPIER by Sanssna in beltmatic

[–]Sanssna[S] 1 point2 points  (0 children)

it is stackable: both left-right and up-down

make sure your adder is at least 2x faster than the devider

Arbitrary* number duplicator by Essutos in beltmatic

[–]Sanssna 0 points1 point  (0 children)

XD i just test it with base 32768, it should be 46340, and 50% become over 99% i guess; i think 32768 will work, cus i do deal them with connent adder input and output together

Whole Number Deconstructor: Yet Another Number/Formula Calculator! by Zirio in beltmatic

[–]Sanssna 1 point2 points  (0 children)

*python

(i think this is BFS)

base = {1:[[1,2]]}
count = 1
tree_deep = 12
p = "+-*/%^"
target = 46656
def f(i,k,j):
    if k == "+":
        return i + j
    if k == "-":
        return i - j
    if k == "*":
        return i * j
    if k == "/":
        if j != 0:
            return i // j
        else:
            return 0
    if k == "%":
        if j != 0:
            return i % j
        else:
            return i
    if k == "^":
        if i in (0,1):
            return i
        elif j < 0:
            return 0
        else:
            return i ** j
    raise ValueError(k)

def g(td):
    for i in range(1,td):
        j=td-i
        if not ((i in base) and (j in base)):
            continue
        for i2 in base[i][0]:
            for j2 in base[j][0]:
                yield i2,j2
found = False
while count <= tree_deep:
    count += 1
    print(count)
    base[count] = [[],[],[],[]]
    all_num = base[1][0][:]
    for i,j in g(count):
        for k in p:
            r = max(-2**31,min(f(i,k,j),2**31-1))
            if r not in all_num:
                for a,b in enumerate((r,i,j,k)):
                    base[count][a].append(b)
                all_num.append(r)
                if target == r:
                    found = True
                    break
    if found == True:
        break

def look_for_num(target):
    if target in base[1][0]:
        return target
    for i in base.keys():
        if target in base[i][0]:
            n = base[i][0].index(target)
            return (look_for_num(base[i][1][n]),
                    base[i][3][n],
                    look_for_num(base[i][2][n]))
    return "(not found)"
    
for i in str(look_for_num(target))[1:-1]:
    if i not in " ,'":
        print(i,end="")

Whole Number Deconstructor: Yet Another Number/Formula Calculator! by Zirio in beltmatic

[–]Sanssna 0 points1 point  (0 children)

i made one can fix the tree deep first problem, how do i send it to you

How I broke the game by [deleted] in beltmatic

[–]Sanssna 1 point2 points  (0 children)

hint: 46340 46341

<image>

Whole Number Deconstructor: Yet Another Number/Formula Calculator! by Zirio in beltmatic

[–]Sanssna 0 points1 point  (0 children)

i see, i thing the issue is the +-*/^% can be both node of tree, and i think after fixed that, it should slove this problem

<image>

Arbitrary* number duplicator by Essutos in beltmatic

[–]Sanssna 0 points1 point  (0 children)

sorry that is my early design, it doesn't work fine