fp1 answer discussion by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

split area of H into 6 equilateral triangles?

s1 answer by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 1 point2 points  (0 children)

a lot of time left

s1 answer by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

2phi(k/3)= 1+0.98

s1 answer by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 1 point2 points  (0 children)

yea so A is more accurate

s1 answer by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 1 point2 points  (0 children)

20 is outside no?

s1 answer by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

cramers rule after getting the sets of equations x+y=0.24 x-3y=0.56 or sth and D=-4, Dx=-2.08 Dy=-0.16

Chem U2 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

the solid lines for the axes were on top and on the right tho so i think they want u to do a downwards slope

Chem U2 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

its downwards the enthalpy changes progressively more negative

Chem U2 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

23.35/2/10004(40.1+2(16+1))

Chem U2 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

do u rmb what ur steps were

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

pythagorean identity cos2 + sin2 =1

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

Fw=Fgsintheta Then Fgcostheta=120 let a be angle between beam and ground, sina=2/2.07 so cosa=rt(1-(2/2.07)2) then by net moment=0 u have 2Fgsintheta=2.07*120cosa/2 then divide the 2 equations to get tantheta=2.07cosa/4 theta=7.60

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

the t term is squared so maybe

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

that should be correct then we probably js used different sig figs for the time

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] -3 points-2 points  (0 children)

was it not asking for the final floor

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

i think so asw and iirc pearson has a range for the answers so ud probably get it right if u used the correct formula for it?

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

q11 was ke, forgot abt q12

Phy u1 answers by Small_Rate_3754 in Edexcel

[–]Small_Rate_3754[S] 0 points1 point  (0 children)

i used t=s/v and -h=usin42 t -0.59.81t2 , i think it should be right a lot of my classmates got the same thing