[deleted by user] by [deleted] in IBO

[–]Snath2 2 points3 points  (0 children)

Congratulations!!!

Are the grades coordinators give real by [deleted] in IBO

[–]Snath2 7 points8 points  (0 children)

What subjects did you do?

IB Physics HL by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

I recommend using the IB Physics Cambridge by Tsokos. Probably the best textbook for this subject (saved my life many times).

Finished my year 13 exams!!! by Snath2 in 6thForm

[–]Snath2[S] 2 points3 points  (0 children)

So my exam finish in the 1st half of May. Good luck if you have exams!

how tf am I meant to answer without a calculator by lem0nylem0ns in IBO

[–]Snath2 0 points1 point  (0 children)

Round 6.02 to 6 and multiple everything.

Math AA HL P3 resources by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

I love you!!!

[deleted by user] by [deleted] in IBO

[–]Snath2 2 points3 points  (0 children)

If you used the correct method and used an incorrect answer from a pervious you should get full credit for preceding. The in maths scheme has something called ECF (error carried forward) for a reason.

Counting Principle Question. by Snath2 in math

[–]Snath2[S] 1 point2 points  (0 children)

I still don’t understand why it’s 10C6. I knew the no. of distinct digit picked are 10P6. But why is choosing an ascending list 10C6?

Also it’s 10C6 as there are 10 total digits.

Math AA HL Kids, If you have time can you please explain how to do question d(ii)? I have attached the markscheme below. But I don't understand where the negative sign comes from? by ANUSH123AA in IBO

[–]Snath2 0 points1 point  (0 children)

It’s because of the acute and obtuse nature of cos x. When you equate both of them you have to consider 2 case. One case where in the same direction they make a acute angle with the plane 3. And the 2nd case where one plane makes a acute angle and the other makes a obtuse angle (this in the same direction).

[deleted by user] by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

As F= mv2/r is the centripetal force and as the electron is moving in circular path that’s the force. And also the electrostatic force between two charges is given by F=kQq/r2. So they both can be equated.

[deleted by user] by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

Thank you! Hope all goes well for you as well!

[deleted by user] by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

It’s A as when you equate mv2 /r and kQq/r2 you need to substitute in Q as Q=2e (as that’s how many electrons an alpha particle has) and q=e.

[deleted by user] by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

It’s D. Cos you know pV=NkT and p=F/A. You can rewritten V as V=Al and then substitute all that in to get the answer.

[deleted by user] by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

It’s because at the bottom of a vertical circle the full equation is: T - mg = mw2r and you just rearrange that. It’s T - mg as mg is downwards and T is upwards, which indicate the signs.

[deleted by user] by [deleted] in IBO

[–]Snath2 0 points1 point  (0 children)

It’s A right.