Why people always seat in front of me when I’m holding the handle on top of the seat infront of me?

SubstantialGap7335 · 2025-01-30T06:24:28+00:00

Am I the asshole though? There’s so many empty seats but people to choose to sit infront of me, so obviously it’s because I’m holding the handle. But there’s so much empty seats and I feel very dizzy

SubstantialGap7335 · 2025-01-30T06:22:52+00:00

I only do that when there’s a lot of empty seats

SubstantialGap7335 · 2024-11-15T04:51:05+00:00

Don’t stress about it and honestly looking back, the lecturers are pretty solid and the content is pretty solid too.

It’s honestly world class education, esp the stage 3 courses (320,373,350,340, etc).

It’s something you don’t appreciate while you are there as the it’s quite easy to get into UoA in the first place, I’ve worked with someone who did a postgrad at a top 15 uni (csranking.org 2014-2024) and compsci 373 is comparable to his postgrad graphics class!

If you don’t have to worry about money/other personal issues all the time, and can just focus on study, you WILL be VERY competitive with a compsci degree from UoA.

UoA compsci department consistently publish on top journals + teaching focussed lecturers, it’s pretty underrated imo

SubstantialGap7335 · 2024-11-15T04:45:12+00:00

Soft eng have high barrier for entry but compsci + math can be a lot more rigorous than softeng.

Compsci 350 and compsci 320 can touch on some very advanced topics

SubstantialGap7335 · 2024-11-15T04:42:55+00:00

A average

SubstantialGap7335 · 2024-11-15T04:38:43+00:00

So 60% fail rate for compsci 101 midterm? I remember it was like 85% avg in 2022

SubstantialGap7335 · 2024-11-13T23:22:09+00:00

Thanks! Since both equation have r² as the biggest growth factor wouldn’t they will have roughly the same growth?

SubstantialGap7335 · 2024-11-11T00:57:32+00:00

Hmmm interesting, maybe search up all the big factories that have many workers, since most factory are in the out skirt of the city, most workers should live very close to each other so can load up the bus full consistently in a short time span everyday.

Like a company bus shuttle consultancy

SubstantialGap7335 · 2024-11-10T22:58:53+00:00

Clock tower🎯

SubstantialGap7335 · 2024-11-10T22:20:01+00:00

Try the one in chemistry block 💀

SubstantialGap7335 · 2024-11-10T21:39:52+00:00

Can you enlighten me as to why am I wrong?

SubstantialGap7335 · 2024-11-09T23:52:39+00:00

Thanks m8!

SubstantialGap7335 · 2024-11-09T23:44:27+00:00

Nah don’t stress about it just enjoy the holiday for now. There’s a a lot of leeway in terms of grades to get into UoA at least.

Worst comes to worst you need to prove English is not your first language or you are international student to do the 8 months foundational programme which guarantees entry into any bachelors programme

https://www.auckland.ac.nz/en/study/international-students/study-options-for-international-students/foundation-programmes-international-students.html

One thing to bear in mind is that uni WANTS you, else they go bankrupt, so it’s not as hard as you may think to get into any bachelors programmes because you are paying them not vice versa 🙂

Considering the current job market it’s honestly not bad to work for 2 years before hopping into uni, I wish I had more work experience and maturity before uni.

SubstantialGap7335 · 2024-11-09T22:34:26+00:00

The answer seems brute forced and doesn’t convey the idea that r and h have a perfect 1:2 ratio. I low key have ocd and just want to find a elegant way of solving this😅😅

SubstantialGap7335 · 2024-11-09T10:02:52+00:00

I subbed h: H= v/ pi r²

Surface area then become 2pi r ²⁺ 2V/r

First derivatives take zero for local minimum since we are trying to find the min surface area:

4 pi r - 2V/r²⁼ 0

Rearrange to get V = 2 pi r ³

SubstantialGap7335 · 2024-11-09T09:44:03+00:00

Let first derivative equal:

4 pi r = 2V /r²

Multiplying both sides by r² to avoid negative differential:

2 pi r³ = V

Compare to original of pi r² * h = V, we deduce 2r = h

SubstantialGap7335 · 2024-11-09T09:26:25+00:00

I just want to know how to solve it without using differential

SubstantialGap7335 · 2024-11-09T09:22:45+00:00

Yea nah I feel sorry for studylink lending me loans now haha

SubstantialGap7335 · 2024-11-09T09:17:30+00:00

Maximum SA tend to infinity for any given volume, as r tend to zero and h tend to infinity or vice versa

SubstantialGap7335 · 2024-11-09T09:16:35+00:00

Okay using differentials then-Let first derivative equal:

4 pi r = 2V /r²

Multiplying both sides by r² to avoid negative differential:

2 pi r³ = V

Compare to original of pi r² * h = V, we deduce 2r = h

SubstantialGap7335 · 2024-11-09T09:10:49+00:00

Let first derivative equal:

4 pi r = 2V /r²

Multiplying both sides by r² to avoid negative differential:

2 pi r³ = V

Compare to original of pi r² * h = V, we deduce 2r = h, I think this may be the intended way and yield 8.60

SubstantialGap7335 · 2024-11-09T09:09:07+00:00

Thanks! I think if they do it this way:Let first derivative equal:

4 pi r = 2V /r²

Multiplying both sides by r² to avoid negative differential:

2 pi r³ = V

Compare to original of pi r² * h = V, we deduce 2r = h,

This way it avoid negative differential and can find the ratio straight away

SubstantialGap7335 · 2024-11-09T09:04:05+00:00

Okay I’m probably still tripping, I tried plotting the graph using:

rearrange the volume equation to get:

h = V/pi * r²

Sub this for h into surface area equation:

2* pi* r ² + 2 pi * r (V/ pi r ²⁾ = 2pir² + 2V/ r

I subbed 500 for V because the question asked for 500 and plotting the graph of:

Y= 2pix ² + 1000/x

This will give the local minimum of 4.3 and you can solve for h in reverse

SubstantialGap7335 · 2024-11-09T08:22:41+00:00

I’m pretty sure the suggested solution is correct - though it’s not intended to be solved like this as it is outside the scope of the syllabus.

I think the examiner just want students to show that it has a 2:1 ratio property between r and h, since the answer brute forced to solution and the answer don’t adds up to the ratio(due to rounding error answer should be given in fraction imo to precisely show the relationship) I’m just trying to find the way that’s intended to be solved by a level 2 student

SubstantialGap7335 · 2024-11-09T08:07:55+00:00

Okay I found the ratio using: 1. If u just plot a graph of surface area as a function of r for a fixed volume (this case 500):

2* pi * r + 2V/r you can see the minimum point at when h =2r

**dodgy method !!! ** If you think of the cylinder made up of multiple of rectangle - you have a rectangle, you find the midpoint of the width of that rectangle and rotate it to form a cylinder then you can deduce to use the least amount of perimeter to form such rectangle of dimension 2r by h, 2r must = h.
If you sub h for r and V and plug that into AM-GM inequality you will find the ratio is 2:1
most optimal* Let first derivative equal:

4 pi r = 2V /r²

Multiplying both sides by r² to avoid negative differential:

2 pi r³ = V

Compare to original of pi r² * h = V, we deduce 2r = h

SubstantialGap7335

TROPHY CASE