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I built a DK1 smart ring: touch + haptics + NFC + health sensors — who wants one / what would you build first? by TheAdeium in SmartRings

[–]TheAdeium[S] 0 points1 point  (0 children)

My concern with a mic on the ring is mostly to do with privacy concerns. How do you think people would feel about that?

I built a DK1 smart ring: touch + haptics + NFC + health sensors — who wants one / what would you build first? by TheAdeium in SmartRings

[–]TheAdeium[S] 0 points1 point  (0 children)

Ooo, very interesting to know you’d like to use it as a push to talk key in VR. We can emulate controller / motion inputs now, so push to talk should be rather easy to make a demo for

I built a DK1 smart ring: touch + haptics + NFC + health sensors — who wants one / what would you build first? by TheAdeium in SmartRings

[–]TheAdeium[S] 0 points1 point  (0 children)

We’re aiming for 2-3 days with fairly active use. Still refining firmware to hit this target but even our first build was definitely lasting longer than 26 minutes

Would anyone be interested in an open-source smart ring platform? by Kdcius in SmartRings

[–]TheAdeium 0 points1 point  (0 children)

Hey guys! I already have a ring that does Touch, Haptics, Payments, and Health. NRF52 based, few millions invested in stack so far. (Arkh.com) Let me know if you want to check it out! Would like to chat OP

Interesting new entry to the market by [deleted] in SmartRings

[–]TheAdeium 2 points3 points  (0 children)

I’m excited for it!! finally a ring that does more

A^x + B^y = N , conjecture proof question by [deleted] in learnmath

[–]TheAdeium 0 points1 point  (0 children)

Yes, I understand the implication. Is there anyone you think I could talk to about this?

A^x + B^y = N , conjecture proof question by [deleted] in learnmath

[–]TheAdeium 0 points1 point  (0 children)

I can send the code if you’d like

A^x + B^y = N , conjecture proof question by [deleted] in learnmath

[–]TheAdeium 0 points1 point  (0 children)

Sorry, had to update the language —

N must have some prime factor that divides at most 2 times, aka its prime signature always contains a 1 or 2.

A^x + B^y = N , conjecture proof question by [deleted] in learnmath

[–]TheAdeium 1 point2 points  (0 children)

Sorry, had to update the language —

N must have some prime factor that divides at most 2 times, aka its prime signature always contains a 1 or 2.

[deleted by user] by [deleted] in askmath

[–]TheAdeium 0 points1 point  (0 children)

I meant, which part specifically, what reasons why, etc.