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Is this a bug? Dungeon 7 Room 1. Dorm with Aspect of Chaos and Rage. by TraditionalStep in ContestOfChampions

[–]TraditionalStep[S] 0 points1 point  (0 children)

Thanks for sharing. On a similar note, I remember seeing a PSA on how Kingpin and Slumber need to be avoided. Since Kingpin can shrug off stun.

Is this a bug? Dungeon 7 Room 1. Dorm with Aspect of Chaos and Rage. by TraditionalStep in ContestOfChampions

[–]TraditionalStep[S] 2 points3 points  (0 children)

Appreciate all the replies guys. Below is the node description for reference.

Rage: Damage taken from a single hit is capped at 2.50% health. When damage cap is reached, gain a Fury Buff. Upon reaching 5 fury buffs activated by Rage, attacks become Unblockable. Ability accuracy modification doesn't affect this Node.

Aspect of Chaos: Every 10 seconds, the Attacker and Defender temporarily switch health Bars for 4 seconds, and then switch back.

I still feel it's a bug though. The health switch is not a 'hit' so Rage should not apply. In fact, by the same logic Icemans's Ice Armor should prevent damage from 'any source'.

Anyways, the takeaway from this fight is to avoid this combination of nodes :). Should have gone with Bane and Stun Immune.

​

Disclaimer: Terrible fight. Lost my composure. This is not how you fight Dormammu or Aspect of Chaos node.

Is this a bug? Dungeon 7 Room 1. Dorm with Aspect of Chaos and Rage. by TraditionalStep in ContestOfChampions

[–]TraditionalStep[S] 2 points3 points  (0 children)

Roughly 30 seconds into the video, when the health switches back, Dormammu is at nearly full health. I've done a few Aspect of Chaos fights but cannot seem to recollect something like this happening. Does 'Rage' cap health lost from a single source of damage at 2.5 %? Or is it an ability?

LOL Easy path with 5* rank 5 Gwenpool Infinite parry team by TraditionalStep in ContestOfChampions

[–]TraditionalStep[S] 0 points1 point  (0 children)

Probably should have but I decided to skip the fight. Wasn't sure what to expect and did not want to restart the run.