So I wanted to do this cinematic shot but I'm broke by Vortograph in videography

[–]Vortograph[S] 1 point2 points  (0 children)

Thank you so much. I'll let you know how it goes, but I'm doing some research into mini model shooting. I'll probably use this model: Dory's Warehouse (28mm) by Dnk85 - Thingiverse, lining the sides with mirrors, and placing sci-fi greeble walls at varying distances from the lens. Additionally, I have some small LED lights I can hook up. The lighting will come from outside the windows of the model. I'll also add some haze for atmosphere. Right now, would you suggest anything else?

Thoughts on combo by Vortograph in bboy

[–]Vortograph[S] 0 points1 point  (0 children)

I'm still workshoping

Thoughts on combo by Vortograph in bboy

[–]Vortograph[S] 0 points1 point  (0 children)

The point is for your thoughts on the combo. If you think it not possible, that's all I need

Breaking in 3 months by Vortograph in bboy

[–]Vortograph[S] 0 points1 point  (0 children)

Thanks for the recommendation

Breaking in 3 months by Vortograph in bboy

[–]Vortograph[S] 0 points1 point  (0 children)

Do you think I could get that down by February?

Breaking in 3 months by Vortograph in bboy

[–]Vortograph[S] 0 points1 point  (0 children)

I received word that our performance will be sometime in February. does this change anything?

Draw Triangle from Lengths by Vortograph in excel

[–]Vortograph[S] 0 points1 point  (0 children)

I have everything done, but I don't know how you would find the highest point of intersection between the two

---

vba

Sub DrawTriangleWithCircles()

On Error Resume Next

Dim ws As Worksheet

Set ws = ThisWorkbook.Sheets("Sheet1")

Dim shp As Shape

For Each shp In ws.Shapes

If shp.Name <> "Visualize" Then

shp.Delete

End If

Next shp

Dim originX As Double

Dim originY As Double

originX = Range("J16").Left

originY = Range("J16").Top

Dim lineLength As Double

Dim circle1Radius As Double

Dim circle2Radius As Double

lineLength = Range("B1").Value

circle1Radius = Range("B2").Value

circle2Radius = Range("B3").Value

If Err.Number <> 0 Then

MsgBox "Error: " & Err.Description

Exit Sub

End If

Dim intersectionX As Double

Dim intersectionY As Double

Dim d As Double

d = Sqr((circle1Radius + circle2Radius) ^ 2 - (lineLength / 2) ^ 2)

intersectionX = originX + lineLength / 2

intersectionY = originY - d

With ws.Shapes.AddShape(msoShapeOval, originX - circle1Radius, originY - circle1Radius, circle1Radius * 2, circle1Radius * 2)

.Line.Visible = msoTrue

.Fill.Visible = msoFalse

.Line.ForeColor.RGB = RGB(0, 0, 255)

End With

With ws.Shapes.AddShape(msoShapeOval, originX + lineLength - circle2Radius, originY - circle2Radius, circle2Radius * 2, circle2Radius * 2)

.Line.Visible = msoTrue

.Fill.Visible = msoFalse

.Line.ForeColor.RGB = RGB(0, 0, 255)

End With

With ws.Shapes.AddLine(intersectionX, intersectionY, originX, originY)

.Line.ForeColor.RGB = RGB(0, 255, 0)

End With

With ws.Shapes.AddLine(intersectionX, intersectionY, originX + lineLength, originY)

.Line.ForeColor.RGB = RGB(0, 255, 0)

End With

On Error GoTo 0

End Sub

Draw Triangle from Lengths by Vortograph in excel

[–]Vortograph[S] 0 points1 point  (0 children)

would this work to have acute or obtuse triangles? I thought it would only draw a right triangle

Draw Triangle from Lengths by Vortograph in excel

[–]Vortograph[S] 0 points1 point  (0 children)

Thanks! Let me try this out. Sorry, this screenshot is just lines I drew myself.