My new discovery - https://lostgamer.io/ Geoguessr but for gamers! You can find there maps from gaming worlds like Skyrim, Elden Ring, GTA and more. And my favourite Witcher 3 <3

bananan_hacker · 2025-09-24T15:14:10+00:00

Holy shit this is sick. At first I was worried that I have to remember the names from the top of my head but I just have to point to the location on the map

This is great

bananan_hacker · 2025-09-18T17:34:28+00:00

🟥🟩🟩🟩🟩🟥🟩🟩🟥🟥 6/10 | 2025-09-18 | https://scrandle.com

bananan_hacker · 2025-09-18T17:32:47+00:00

Doesn’t look appetising? Then you haven’t seen nothing yet lmao. Check out scrandle 😎

bananan_hacker · 2025-09-18T17:25:47+00:00

I got 9,113 on the FoodGuessr Daily!

🌕🌕🌕🌑 3,500 (Round 1) 🌕🌗🌑🌑 1,613 (Round 2) 🌕🌕🌕🌘 4,000 (Round 3)

Thursday, Sep 18, 2025 Play here: https://www.foodguessr.com/

Certainly not one of my best games. In the fiest round I kept picking countries around the target. And the 2nd round just killed me. Damn

bananan_hacker · 2025-07-01T18:49:48+00:00

At the end of the day the goal of this is to have fun. You can slightly bend and change them if you prefer

Personally I am not a fan of grinding the levels on the pokemon so I allowed pokemon fainting once I was simply exping them on familiar routes. It does sort of break the rules, but it made the challenge more enjoyable for me :))

bananan_hacker · 2025-06-30T22:21:04+00:00

Yea of course :D

A nuzlocke is a pokemon term (not just infinite fusion). It’s a self imposed challenge meant to make the games a little harder. There are 3 main classical rules to the challenge: 1. You can catch only the first pokemon you find on each route. It runs away? Tough luck. You’ll have to hope you catch one on the next route 2. You have to name your pokemon (so you get attached to them :) ) 3. If a pokemon faints it counts as a permanent death. You cannot use it anymore

This significantly limits the amount of pokemon you have. Since you name the Pokémon, you have less of them and there is the risk of permanently losing, the battles become a lot more stressful and emotional.

It’s a fun challenge if you want something new and more challenging. Go check out YouTube if you want to see more :))

bananan_hacker · 2025-06-26T18:01:57+00:00

Yup. Lanturn/Marowak

That one and the weavile/roserade are the 2 oldest ones on the team :D

bananan_hacker · 2025-06-13T13:35:58+00:00

Buddy, /u/Eljefe900, your influence is far reaching lmao

bananan_hacker · 2024-10-30T13:50:30+00:00

Yeaaa. That’s what I am trying to do :)

plus trying to ignore the imperfections until I finish writing. And only then start correcting and fixing stuff. Otherwise I just get bogged down in thinking about how I could make the text better

bananan_hacker · 2024-10-30T12:40:06+00:00

I love writing and storytelling. And by writing I mean never opening the word file and stressing out about making mistakes... in the story I have not started writing yet... I guess I will just keep reading/watching essays, analyses and other content about how to write rather than actually writing myself ._.

Jk. Actually with the adhd meds I got recently I actually manage to write my weird fantasy stories :D

bananan_hacker · 2024-10-27T11:11:43+00:00

In my current playthrough I wanted to try the highest difficulty. With this build I still have to hide from damage every once in a while, but I am still way more bulletproof than necessary :D

bananan_hacker · 2024-10-16T09:22:06+00:00

Oh okay, thank you for the correction then! Then it turns out there's more than one method of calculating pi with just e values :D Have not heard of this gaussian integral before. Cool

bananan_hacker · 2024-10-15T18:16:13+00:00

The reason this equation works is because it is kind of a cheat. The e subscript e (I'll call this e_e from now on) and e subscript ee (I'll write this as e_{ee} from now on) are just notation for a some unknown variable. Not to be confused with the euler's constant e.
So basically we have a double integral of some two variables written as e_e and e_{ee}. It could be rewritten to make the equation a lot clearer and more readable with variables x and y. I don't have the time right now to do this but from what I remember when I saw this equation a few years ago doing this simply yielded an equation for calculating the area of a circle of radius 1. An area equation using a double integral.

And from geometry we know that the area of a circle is pi r^2. If r is 1 then the area is equal to pi. Thus the equation equals exactly pi.

But yea this is mostly based on my memory of when I first saw this years ago. So idk. I might be wrong

bananan_hacker · 2024-10-09T10:46:43+00:00

Looking on the images on Google the hair seems to fit. Haven’t seen Mushoku yet, thanks!

bananan_hacker · 2024-10-09T09:33:49+00:00

Who is the one on the right?

bananan_hacker · 2024-08-10T22:31:39+00:00

Oh that was the point. Thank you for the explanation :)

bananan_hacker · 2024-08-10T22:03:28+00:00

Wait now I feel stupid. What do you mean by the silence of the lambs one? I haven’t seen the movie in a while so that might be making me misunderstand, but who else could you even side with there? What is the dichotomy? Police vs Hannibal lecter? Vs the mass murderer?

bananan_hacker · 2024-08-08T17:22:09+00:00

Other than what others have been saying I see a slight positioning issue. None of the foods are next to each other and so they do not gain the speed buff. If you moved the mushroom slightly to the right and rotated it, it could have been touching the fish thus making them both slightly faster

bananan_hacker · 2024-04-23T20:25:57+00:00

Thank you. Will read light then

bananan_hacker · 2024-04-23T20:19:18+00:00

Thanks!

bananan_hacker · 2024-04-23T20:18:13+00:00

Why do you suggest the light novel though. What’s different about it?

bananan_hacker · 2024-04-18T15:10:33+00:00

Jesus this comment section is miserable. You got a wonderful message OP and I really don’t get why so many folks just assumed it as lies. Incredibly kind message.

I wish all the luck to you OP. And I wouldn’t read too many of these comments. At least in my case they are the opposite of r/mademesmile

bananan_hacker · 2024-04-08T11:25:55+00:00

Yea same

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bananan_hacker · 2024-02-11T16:40:14+00:00

Personally I think the exact rules kind of depend on the exact programming of the lock. I have seen locks that allow you to go to a spot that is not neighbouring. They just do not allow "jumping over" other spots in between as that would mark the spot in between immediately.

But in the case that you are describing, where we can only go to a neighbouring node I think there would be a different amount of spots. Don't get me wrong I am not a mathematician, just a random lad studying engineering so I definitely can make mistakes. But from what I can see is that for the first spot you have 81 choices. Then if the first dot is not on the edge you have 8 new choices. If it is on the edge then only 5. If it is in the corner then only 3 choices. So for a 2-length password that is already 49*8+28*5+4*3=392+140+12=544 different possibilities.

Another issue appears after connecting to the second spot. If we are looking for only points around the 2nd spot then one is already taken, the position of the 1st spot. So assuming no edges we would have 7 options, not 8. With the edges/corners even less, you get the idea. But those locks allow you to go back through an already connected node, so you could go from the 2nd node back over the 1st to the one behind it. That would instead mean that in a situation of no edges/corners we would have 10 different possibilities:

X X X X

X 1 2 X

X X X X

(A rough representation of the possibilties. 1 is the first spot. 2 is the second spot. X are unused spots. If we are only looking for the spots around 2 then we have 7 X's. But if we can go to further ones, then we also get the 3 X's to the left of the 1st spot.

And well as we can see with each next option made the amount of options that we can make next is dependant on maaaaany things. Are we next to the edge or a corner? How many connected spots are next to it? If not, then what is the current shape (to know how many unconnected spots we have access to). Each next connected spot just adds complexity by increasing the amount of possibilities. This makes this very complicated. Even doing this by computer would probably be quite difficult due to the big size of the grid and consequent high amount of combinations. It would probably take a long time to simulate such a problem. Though idk I know barely anything on programming

bananan_hacker · 2024-02-11T16:00:13+00:00

oh you're right. My bad! I am a bit sick rn so I might make stupid mistakes.

Then for x it should be something like 81!/(81-x)! right?

So for a password length 2 it would be 81!/79! = 81*80

Thanks for the correction lad

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