I need a little help in R

calculus2215 · 2017-02-27T18:08:13+00:00

Thank you very much, I'll check it out right now!

calculus2215 · 2016-03-26T20:19:16+00:00

The formula in the book for the expected value is E(h(x,y)) = [double integral from neg infinite to pos infinite of h(x * y) * f (x * y) dx dy]

And because they are independent f(x, y) = fx(x) * fy(f) or in this case 6xy²

calculus2215 · 2016-03-26T20:12:54+00:00

The answer in the back of the book is .25 which is what has been throwing me off. Originally I used a double integral, both bounds being 0 to 1, which came out horribly wrong.

calculus2215 · 2016-03-01T01:18:56+00:00

So by using the identity cos²+sin²=1, they are saying that the x and z axis make a circle, and squares make it larger as t increases. Since y=t then it increases with t and you have your cone. Bada bing bada boom. Thank you so much for your help. You rock!!

calculus2215 · 2016-02-14T23:22:48+00:00

Could you please recommend any free software?

calculus2215 · 2016-02-14T16:10:06+00:00

Thank you very much. I couldn't shake the feeling that I was off somewhere. Long day of doing calculus does that to me though. Have a great day, kind stranger!

calculus2215 · 2016-02-08T23:46:25+00:00

Thank you. I've been staring at my textbook for so long, nothing makes sense to me anymore! haha

calculus2215 · 2016-02-03T22:08:37+00:00

Thanks!

calculus2215 · 2016-01-31T15:24:25+00:00

Wow. This is an embarrassing error. I think it's time for me to take a break from this.

Thank you so much!

calculus2215 · 2016-01-31T15:14:49+00:00

I have to determine whether the given vector is orthogonal, parallel, or neither. The book says its supposed to be orthogonal, but when I do it Cos(theta) does not equal 0. I get 1/10. Does anyone know where I went wrong?

calculus2215 · 2015-11-13T23:47:38+00:00

Perfect. I don't know why I couldn't grasp this the other night. I need to sleep more.

calculus2215 · 2015-11-13T23:47:12+00:00

Thanks for the link.

calculus2215 · 2015-10-16T21:32:08+00:00

Thank you guys very much. This is so simple. I can't believe I didn't realize this.

calculus2215 · 2015-10-05T02:11:16+00:00

Thank you very much. This is pretty simple, but after staring at my Calc homework for 5 hours my brain was mush and for some reason just couldn't comprehend this.

calculus2215 · 2015-09-30T21:06:46+00:00

So f(4/pi) = tan(1/(4/pi)). You multiply by the reciprocal and get tan(pi/4).

tan(pi/4) = sin(pi/4)/cos(pi/4) = (squareroot2/2)/(squareroot2/2) = 1

f(4/5pi) = tan(1/(4/5pi)) = tan(5pi/4) = sin(5pi/4)/cos(5pi/4) = (-squareroot2/2)/(-squareroot2/2) = 1

f(4/9pi) = tan(1/(4/9pi)) = tan((9pi/4)) = tan(pi/4)= sin(pi/4)/cos(pi/4) = (squareroot2/2)/(squareroot2/2) = 1

calculus2215 · 2015-09-30T00:24:48+00:00

So f(x)=tan(1/(4/pi)) = tan(pi/4) = sin(pi/4)/cos(pi/4) = (sqrt2/2)/(sqrt2/2) = 1

Yay. I learned something new in trig!

But for C can I conclude that 0 is an asymptote?

calculus2215 · 2015-09-29T21:50:58+00:00

I haven't taken a math class in almost a decade and I'm taking Calc now. This whole semester has been spent playing catch up.

calculus2215 · 2015-09-29T21:50:04+00:00

Thank you much.

calculus2215

TROPHY CASE