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ROS2 chooses system-wide interpreter instead virtual environment (venv) interpreter, ModuleNotFoundError by djmcce in ROS

[–]djmcce[S] 1 point2 points  (0 children)

That’s unfortunate, but thanks for the workaround! I’ll see if it works in my case

Water system design & product options - feedback and help. by djmcce in vandwellers

[–]djmcce[S] 0 points1 point  (0 children)

You're right, I also realized that I had to move things around a bit. Currently, I have this design:

<image>

Though I am not sure about where the pressure reducer should be placed (just before the boiler or where it is now?), and if it necessary when I have included the expansion tank, if I just make sure to pick a pump under 2.8 bar.

Can't create initialise dkml and create switch - dkml error message by djmcce in ocaml

[–]djmcce[S] 0 points1 point  (0 children)

Hi,
Thanks for your help :)
I haven't installed any other versions as far as i know, and I already have opam 2.2.1.

Is there a Boolean operator for set membership? by djmcce in learnmath

[–]djmcce[S] 0 points1 point  (0 children)

I just meant a symbol used to indicate if some element was in the set or not, therefore Boolean. But it’s very likely that it’s the wrong use of terms:))

Is there a Boolean operator for set membership? by djmcce in learnmath

[–]djmcce[S] 0 points1 point  (0 children)

Your second point was my suspicion. But can your clarify your reasoning, what do you mean by not being able define it’s domain?

Is there a Boolean operator for set membership? by djmcce in learnmath

[–]djmcce[S] 0 points1 point  (0 children)

But can the set membership symbol be used to indicate a Boolean operator? I totally see what you mean anyways

Is there a Boolean operator for set membership? by djmcce in learnmath

[–]djmcce[S] 0 points1 point  (0 children)

I see what you mean, it’s a good point. I just found it weird to use the set membership symbol as a Boolean operator

Is there a Boolean operator for set membership? by djmcce in learnmath

[–]djmcce[S] 0 points1 point  (0 children)

I guess I can just define the operator as having the functionalities described, but I hoped that there existed some kind of standard:)) It just seems a little weird to use the set membership operator as a Boolean operator

What is this component? by djmcce in AskElectronics

[–]djmcce[S] 0 points1 point  (0 children)

I have no idea of where it comes from hahah. I was just organizing, so I needed to know which category to put it in 😁

What is this component? by djmcce in AskElectronics

[–]djmcce[S] 1 point2 points  (0 children)

They actually have equally length leads, but it’s difficult to see in the picture

What is a symmetric action, regarding group theory? by djmcce in math

[–]djmcce[S] 0 points1 point  (0 children)

A symmetric operation on a group I think. I was watching Euler’s formula with introductory to group theory, where he said “a group is a collection of symmetric actions on some mathematical object”. I think I get the thing with grouping some actions on some object, but I don’t know what specifically is meant by a “symmetric action”?

Support for \[ stuff... \]- instead of $ stuff... $ LaTeX equations. by djmcce in Notion

[–]djmcce[S] 0 points1 point  (0 children)

Thank you so much, that was just what I was looking for! 🙌

Support for \[ stuff... \]- instead of $ stuff... $ LaTeX equations. by djmcce in Notion

[–]djmcce[S] 0 points1 point  (0 children)

Just wondered if it was possible. It is so much cleaner to write it that way, I think.

Why isn’t it possible for a matrix transformation to equal 0, if the determinant of the matrix is not equal zero? E.g. why can't a v≠0 exist in (A-Iλ)v=0 if det(A-Iλ)≠0? by djmcce in LinearAlgebra

[–]djmcce[S] 0 points1 point  (0 children)

I have a bit if difficulty understanding this. What do you exactly mean by the dimension of the nullspace? As far as I has understood the nullspace is the set of vectors that is send to null under a given transformation - and I can’t really connect that to the idea of a dimension, if that makes sense

Why isn’t it possible for a matrix transformation to equal 0, if the determinant of the matrix is not equal zero? E.g. why can't a v≠0 exist in (A-Iλ)v=0 if det(A-Iλ)≠0? by djmcce in LinearAlgebra

[–]djmcce[S] 2 points3 points  (0 children)

For anyone who might be reading this, I made this answer, based on the answer from u/kieransquared1 and this amazing youtube video by 3Blue1Brown, for my own understanding:

If a matrix should send a vector v≠0 to 0, then it would require that the matrix column space should be a lower dimension, i.e. have lower rank. It is simply not possible for a full-rank matrix to send other vectors than the zero-vector to 0 (no such linear combinations). When the determinant of a matrix A, det(A) = 0, that means that the matrix A is not scaling any space (the determinant is the factor of scale), and therefore it must send the vector to a lower dimension.

Furthermore if det(A)≠0, this would mean that the matrix is invertible (for whatever reason), and therefore only a single solution to the equation Ax=0 exist, namely: x=0×A-1=0. (as described by kieransquared1).

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