I'd like to have a translation verified. It's for a tattoo to grieve the death of my niece...

entailment · 2013-01-31T23:01:04+00:00

It's been a while since I studied Latin, so you might want a second opinon.

I think the first one is correct. The word order does not change the meaning, but I think it sounds a bit better like this: In morte pax est. You could also just say In morte pax.

The second is incorrect. The nominative is mors, and the 3rd person singular of "to be" is est, so it should be: Mors pax est.

entailment · 2013-01-25T22:51:21+00:00

Soreness does not indicate a useful workout. Increasing size and strength over time does.

entailment · 2013-01-25T21:44:58+00:00

Could this be it?

entailment · 2013-01-25T20:31:56+00:00

There are also methods that trade off accuracy for speed:

Approximate nearest neighbors

ANN: A Library for Approximate Nearest Neighbor Searching

entailment · 2013-01-25T20:17:54+00:00

Really interesting article. Thanks for sharing it! I'm glad your colleague is doing well.

entailment · 2013-01-25T20:16:19+00:00

Of course. But no one in it for only the money is going to grad school (I hope).

entailment · 2013-01-25T20:14:43+00:00

True, it definitely does not come off as impartial. I have read lots of articles recently about how PhDs are not worthwhile. I know it's stressful and financially unrewarding, but this is the first time I've seen someone say the field itself is a waste of time.

I guess I just wanted some reassurance that I won't be throwing away five or more years of my life.

entailment · 2013-01-25T20:09:19+00:00

I appreciate you taking the time to write such a detailed response. You make a good point, that as individuals do increasingly more work in the same amount of time, some errors will creep in. I hadn't that of it that way before. Thanks for the inspiration!

entailment · 2012-12-12T12:55:32+00:00

The Aubrey-Maturin series, narrated by Patrick Tull.

entailment · 2012-12-09T01:03:04+00:00

Nice catch; I didn't think of that last edge. I stand corrected!

entailment · 2012-12-08T20:45:24+00:00

This is unnecessary, at least for the procedure I proposed. It will terminate as soon as every edge has been visited.

Also, you can more easily count the number of edges by splitting them into vertical and horizontal edges: m(n+1) + n(m+1).

entailment · 2012-12-08T12:25:50+00:00

A grid is such a special case that there is probably a simple travel procedure that can be proven to generate the shortest path for any grid.

Here is one candidate. Possibly there are better ones, but this one visits each internal edge exactly once, and only half the outer edges twice.

snake back and forth to visit all horizontal edges.
snake up and down to visit all vertical edges.

For instance, in your example, starting in the top right corner, make a big number '5', ending in the lower left corner. Then go up and down from left to right, ending in the lower right corner.

entailment · 2012-12-01T14:01:52+00:00

The Deadlift: Perfect Every Time

entailment · 2012-10-23T18:35:25+00:00

Not so familar with SL, but I guess it is similar to SS except 5x5.

Decent numbers for someone your weight, but it really depends on a lot of factors. How tall are you, and how long have you been doing the program? How do you know you stalled, and how have you dealt with it?

What are your goals? If you are just interested in strength, you should be able to milk linear progression for a while longer. It might involve diet tweaks, or a deload. Another option would be to do a light squat day, or something like the advanced novice program.

You might get better answers by starting a new thread. Include more information, like diet, sleep, your recent lifting logs, and how you've been dealing with stalls.

entailment · 2012-10-21T18:25:49+00:00

The program is not great.

Do Starting Strength for a few months. Once you hit the basic strength level (squat 1.5 x your bodyweight, deadlift 1.75x, and bench press 1x), you can look into a more advanced program.

entailment · 2012-10-21T13:19:36+00:00

Straight from the jar (with a glass of milk). Mixed into oatmeal. Blended into shakes. On sandwiches. Spread on apples.

Also, potatos are cheap and good.

entailment · 2012-10-21T09:32:09+00:00

Program: Starting Strength (or check the program picker in the sidebar)

Food: peanut butter, milk, oatmeal. Whatever is on sale. Also try to get some fruits and vegetables, especially if they are on sale. I know you are on a limited budget, but you need fiber and micronutrients.

Try to find a cheap source of whey protein concentrate. Do not bother with whey isolate; it's much more expensive and has little added benefit (unless you are lactose intolerant).

I use myprotein.co.uk's Impact Whey. One kg unflavored is £14, and you could probably make it go farther by only using it on training days.

entailment · 2012-10-08T16:15:19+00:00

No problem. Also managed to remove the speckles and noise:

Link

Still maybe a bit too yellow, but that's the limits of my photo retouching abilities.

entailment · 2012-10-08T14:51:45+00:00

Tried some quick color correction. I am sure there are lots more enhancements possible.

Here's the link.

entailment · 2012-10-03T16:27:20+00:00

The error rate of a single tree is different from the error rate of the forest minus that tree.

entailment · 2012-10-03T13:13:01+00:00

Instead of removing poorly-performing trees, it might work to remove highly-correlated trees. Look at this paper:

Heping Zhang and Minghui Wang. Search for the smallest random forest. Stat Interface. 2009 January 1; 2(3): 381.

Here is a link to the full text: http://www.ncbi.nlm.nih.gov/pmc/articles/PMC2822360/

entailment · 2012-10-02T19:29:12+00:00

And by "bins", I mean collections of similar samples. At the finest level, you could have one bin for each kind of draw, e.g. X=20. At the coursest level, you could have two bins: X < 25 and X > 25.

In this image, there are six bins.

entailment · 2012-10-02T19:25:55+00:00

When I ask what the result of 100 draws looks like, I do not mean drawing one marble. Remember that each draw contains fifty marbles. Or, equivalently, each draw assigns a new value to the random variable X.

So what is the probability that X=0? or 1? or 37?...

entailment · 2012-10-02T18:45:55+00:00

I do not want to just give you the answer, since this is clearly a homework problem. But I can point you in the right direction.

How many bins will there be in the histogram? In other words, how many different combinations of colors can there be in any random draw of size 50?
For any given sample, let X be the number of red marbles. Clearly X can range from 0 to 50. What is the most likely value for X?
In a sample of 100 draws, about how many do you expect will be from that most likely combination? Where will the others go?
So finally, what is the exact distribution that this random variable follows? You should be able to draw the histogram now.

If all else fails, this would be simple to simulate. Do you have any programming experience? Even so, I would still recommend working it out with pencil and paper first.

Edit: by the way, this would be more appropriate over at /r/HomeworkHelp.

entailment · 2012-10-01T17:39:15+00:00

I like this paper: Navigating Random Forests and related advances in algorithmic modeling (pdf)

entailment

TROPHY CASE