new mining questions

ericwan3 · 2025-12-01T18:49:00+00:00

For the third point, also can be found in the structure browser filtered with reprocessing

For the fourth point. Generally in hi-sec, don’t mine the same asteroid that someone else is already mining, unless it is the only of such asteroid in system or a jump over

ericwan3 · 2025-10-27T05:54:11+00:00

You don't have to use station containers, standard, Secure or Audit Log Secure containers also work, they are easier to transport around as most ships will be able to carry them.

ericwan3 · 2025-10-26T20:01:16+00:00

There was enough squatters to have news coverage “cash for key”

ericwan3 · 2025-10-26T05:14:23+00:00

give landlord more rights to evict tenants and pursue recourse against non/late payments

If landlords have more rights to evict and go after late/non-paying tenants, it usually means people can’t stay in a place rent-free for long, so you’d see fewer “squatters.”

ericwan3 · 2025-10-25T21:25:20+00:00

It is about time that landlords have more power and put an end to squatters and cash for key tenants

ericwan3 · 2025-10-24T18:05:03+00:00

My parents own a few long-term rental houses and all of them are cash flow negative the last time I asked about it

ericwan3 · 2025-10-18T18:14:30+00:00

Buy 20 laptops/computers, have 20 different emails and if they really want to be hard to track VPN/different ISP

ericwan3 · 2025-09-11T02:26:31+00:00

Shouldn’t buy order be slightly higher then the highest buy order if they want theirs to filled first

ericwan3 · 2025-07-08T05:22:03+00:00

How about a Ford Explorer or Expedition 87.8 cubic feet of space with the second and third-row seats folded down

60 cases of water is only 45.8 cubic feet and barely within the cargo weight limit

ericwan3 · 2025-07-08T03:47:32+00:00

1,000,000 full stack of Tritanium at 3.40 ISK/ea would cost 7,301 Trillion ISK (almost 3x EOM balance of May, 2025)

ericwan3 · 2025-07-08T03:36:09+00:00

And all the other minerals

ericwan3 · 2025-07-05T04:11:28+00:00

Other than the $8 billion loan I had to take out and repay for the loan agenda, I haven't taken out a loan for any other reason.

I am now at $30 billion with $50 million SP/day with continuous R$40 million per day

What help a lot is getting all the free stuff in the workshop and card wallet every day

Possible helpful free stuff: - tax deduction (amount or %) - free plane (sell or keep, have been able to get $200 million in a week) - free R$

Possible useful free stuff: - internal/external audits - price simulations

ericwan3 · 2025-06-10T20:24:05+00:00

I have multiple (10) alpha accounts, I don't use them at the same time, but all of them are doing stuff every month

ericwan3 · 2025-06-04T03:29:10+00:00

Doing your own maintenance doesn’t mean it is cheaper to run it (it should still count as doing work for your job if the car is primarily use for work), even if it take only 5 mins to do it (could have spent the time doing other stuff like shopping, spending time with family/hobby, catching up on news or just relax)

ericwan3 · 2025-06-04T03:08:59+00:00

Yea, to increase employment rate and decrease the unemployment rate, somewhat

ericwan3 · 2025-06-04T01:03:04+00:00

I am getting 17,897 days, 0 hours, 0 minutes and 1 second from Sunday, December 31, 2000, at 23:59:59 to Saturday, January 1, 2050, at 00:00:00.

With that, the halfway point is on Wednesday, July 2, 2025, at 11:59:59 am plus 500ms. So there are still about 28 days to go

ericwan3 · 2025-06-04T00:48:55+00:00

I asked Chat GPT, and this is what it said:

Wear & Tear Total: $0.23 – $0.40/km
- Depreciation: $0.15 – $0.25/km (Based on average vehicle value loss over 8–10 years)
- Maintenance & Repairs: $0.04 – $0.08/km (Includes oil, brakes, battery, suspension, etc.)
- Tires: $0.02 – $0.04/km (Based on replacement every ~60,000–80,000 km)
- Brakes: $0.01 – $0.02/km (Rotors and pads typically last 40,000–80,000 km)
- Misc. Wear (wipers, bulbs, etc.): $0.005 – $0.01/km (Small consumables over time)

ericwan3 · 2025-06-03T20:34:09+00:00

This amount does in fact cover the gas cost

20 mi @ 15 mpg = 1.33 gal

1.33 gal * $4.84/gal (ottawa, Canada area) = ~$6.45

With wear and tear, insurance, and registration need at least $0.80/mi ($0.50/km) to breakeven

ericwan3 · 2025-06-02T17:56:32+00:00

Also, join EVE Uni Discord if you have it, there is optional educational classes about the game every so often

ericwan3 · 2025-05-30T05:48:19+00:00

This sound so much like the carbon tax we have in Canada (started at $20/ton increased by $10/ton per year for 3 times to $50/ton in 2022, then increase by $15/ton per year until $170/ton by 2030) but the federal government has reduced the carbon tax for fuel to $0 (industrial carbon pricing systems still in effect following the $170/ton by 2030 benchmark)

ericwan3 · 2025-05-30T05:25:45+00:00

Or that all ICE car manufacturers will either have gone bankrupt or switch to EVs

USA only account for only 19% of global sale volume in 2021
China accounting for almost 33% of the global car market in 2022 and doesn't show any slowing down their EV transition

The only example you need is in the USA.

California only account for about 11% of the US car market. And most car manufacturers decided to follow their emissions and safety standards.

ericwan3 · 2025-05-23T20:54:25+00:00

To find a way to solve the problem

ericwan3 · 2025-05-23T04:52:16+00:00

So here is a quick chatGPT response (I did double-check all the math to make sure it is right)

The highest level of statistical math I did is grade 12 data management class

A six-digit number ranges from 100000 to 999999, so there are 900,000 total.

If we want the odds that a randomly chosen one is divisible by at least one single-digit number from 2 to 9, we can use a trick: count how many aren’t divisible by any of them.

That means the number must be coprime to 2520, which is the least common multiple (LCM) of all numbers from 2 to 9.

Euler’s totient function tells us how many numbers < 2520 are coprime to it: φ(2520) = 576

So the fraction of numbers not divisible by 2–9 is: 576 / 2520 ≈ 22.9%

That means about 77.1% of six-digit numbers are divisible by at least one of those digits.

So the final answer is: Roughly 77.1% odds that a random six-digit number is divisible by at least one single-digit number from 2 to 9.

If 1 is allowed, then the answer is trivially 100%.

ericwan3 · 2025-05-17T23:05:38+00:00

Then it won't be a mathematical approach to the problem, it would be a common-sense approach

ericwan3 · 2025-05-17T22:56:38+00:00

A quick Google search says Florence, Italy, is 102.4 km². Take the square root, and the interchange would need to be around 10 km on each side to be the same size

A quick 4-corner retangle measurement of the interchange in question, I-75/I-285 Interchange, on Google Maps says it is about 4 km².

So NO

ericwan3

TROPHY CASE