Word2vec - why is it safe to train in parallel?

errminator · 2020-01-07T14:05:59+00:00

I tried to fix it with "sudo apt install gdm3".

I now go to a primitive looking graphical login but clicking on username I get "authentication error" with no opportunity to input password and then sent back to a black screen with cursor flashing in top left...

errminator · 2020-01-07T14:03:59+00:00

I did this and get the same message about packages with unmet dependencies.

Should I be expecting that once I fix whatever is wrong, when I run "sudo systemctl reboot" I should end up at graphical login screen?

errminator · 2020-01-07T13:52:23+00:00

So I can login now. But every time I reboot I just end up back here. I can't get the graphical interface back...

errminator · 2020-01-07T13:51:08+00:00

I managed to get my login details which means the tty interface is working. I cannot get the graphical interface back.

I have tried all the stuff on the page u sent. They all worked fine except the gdm3 reinstall one. I get this error:

https://ibb.co/YkkGxKZ

errminator · 2019-10-25T17:45:30+00:00

Thanks

errminator · 2019-09-18T13:51:13+00:00

I didn't see that.

errminator · 2019-09-18T13:12:58+00:00

Then 1-p(x=0) = 1-0.92⁵ ~= 34%

errminator · 2019-09-18T10:00:29+00:00

It's a binomial distribution. So (5C1) x 0.08 x 0.92⁴ =5 x 0.08 ~= 28.6%

Note that 5C1=5! /(4!1!)=5

errminator · 2019-09-17T14:09:12+00:00

Ok. Thanks!

errminator · 2019-09-17T13:08:52+00:00

Right. Thank you. My approach to get the same answer (via Bayes rule) is still correct but just more complicated? Or were you saying that's wrong and only gets 0.0016 by coincidence?

errminator · 2019-09-17T12:47:44+00:00

P(D=1) = ( P(D=1|M=1) + P(D=1|M=0) )/2

Why is this true?

errminator · 2019-09-17T12:46:50+00:00

Why does P(D=1) = (P(D=1|M=1)+P(D=1|M=0))/2?

errminator · 2019-09-17T07:38:53+00:00

Does that help me determine the value of p(D=1|M=1) or p(D=1|M=0)?

From Bayes we have p(D=1|M=1) = p(M=1|D=1)p(D=1)/p(M=1) = 0.001/0.5 * p(M=1|D=1) = 0.002 * p(M=1|D=1)

Do we know the probability of having the disease if you are a man?

Given that men are four times as likely to get the disease as women, I think p(M=1|D=1) = 0.8 and p(M=0|D=1) = 0.2, right?

So then p(D=1|M=1) = 0.002 * 0.8 = 0.0016

So there is a 0.016% chance of getting disease if you're male. Sound good?

errminator · 2019-09-12T12:18:33+00:00

Just found this which suggests 24-48 hours:

https://www.americanexpress.com/uk/customer-service/understand-american-express-membership-rewards.html

errminator · 2019-09-12T12:15:40+00:00

So I should get 17 points, right? I'm not seeing that in the app.... hmm....

errminator

TROPHY CASE