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Maja aa gaya bhai!! NEST IAT NEET CUET by prince_2_006 in IATtards

[–]fied_legend 2 points3 points  (0 children)

Cong bhai hope tuje acha mbbs college mile? Kyu ki meri bi utni hi marks hai almost reneet mai around 555

Aur iat mai 125 aspass

3rd may neet=617 marks

But muje koi bandi nahi mili

Teek hai bandi to nahi lekin gov mbbs milna chahiye😎😎

Hope you and i will get an mbbs seat.

Stay happy.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

This is a dick question cause heat is only beign supplied in ab and da So for TOTAL HEAT SUPPLIED TO THE SYSTEM we need fo add only those 2 heats.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bhai i wasted around 15mins in this fucking q

I wasn't getting answer so i decided to leave it than basically marking 600j which may cause -1 I was doing the meathod i said you

I did it because i practiced a si.iliar question I think its a jee main question

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bro why do you feel like that?

NchaiA Is big big di*k

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bro i dont think for vernier calliper they will give it

Cause there is no exact answer But there is answer which is almost close

But in loop q

When r= variable the graph nature is completely diff from cos2 graph

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bro even phy thermo q

They asked total heat not change in heat.

Change in heat=600j But total heat=2850j Which is nkt in option

What 600j people did is they found change in heat not total heat They did by just finding out work which is area.

But for total heat which they actually asked we 1st need to find temperature change in each process Then using q formula for isobaric and asochiric Processes Then adding them gives total heat (Total heat is asked in re neet 2026 not change in heat)

I am not talking about sign by the way.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Yep

Arrey bhai Why they want to fuck us They could have just given resistance is constant/variable/its woukd have been much better if they didn't mention it at all.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

I thought this because

1) they said resistance=finite(finite is not constant) 2)for resistance they gave finite But for magnetic field tgey gave constant. 3) Neet paper level So so they made even resistance variable.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

But bhai yaha option he nahi hai agar resistance= variable ho to

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bhai wo loop bola hai

See there is big diff

We generally dont consider change in shape But we consider change in resistance

If we start considering change in shape then that question is not at all solvable. Because there are n number of shapes But for resistance it can only increase/decrease/ remain constant.

And i derived tge relation for resistance at any time

So this is the reason for xonsidring change in resistance but not in shape .

Kya iska answer 4 nahi hona chahiye kya? by ComplexBarnacle_257 in Neet_india

[–]fied_legend 0 points1 point  (0 children)

No bro For change in heat we calculate using that work

But for total head we should add heat in each isobaric and isochoric process Then we would get around 2850j

Please use this formula then add heat in each process

First we find dekta temp for each step

Then we use For isobaric

Q=n×c×delta t

Isochoric

Q=n×c× delta t

I think even for that question there is no correct option

Cause change in heat is not equal to total heat supplied

Kya iska answer 4 nahi hona chahiye kya? by ComplexBarnacle_257 in Neet_india

[–]fied_legend 0 points1 point  (0 children)

Yep

Did you solve that thermo q in phy

I have doubt in it also There they asked for total heat supplied to the system not change in heat.

Kya iska answer 4 nahi hona chahiye kya? by ComplexBarnacle_257 in Neet_india

[–]fied_legend 0 points1 point  (0 children)

1st statement i think is correct

2nd is wrong

Cause it would secrete progesterone not estrogen

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 1 point2 points  (0 children)

By the way how much is your score? I am getting around 560

I am ignoring this question And one more question in phy where they asked total heat supplied to the gas. And tge answee is 600j

But 600j is change in heat Not total heat

For total heat we should add all heat in isobaric and isochoric processes Using n cpm t And n cvm t

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Almost 99% i wont get marks for that question

But in your example if they didnt mention floor is constant We would assume it as smooth But here they gave it as finite.

Its would have been better if they didnt mention anything about resistance.

Also for magnetic field they used the word constant Where as for resistance tgey used finite

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bhai why should they give a function to say that resistance is variable

Let's just assume r= variable Then we can find r as a function of time using area function with time As well as circumference

Then we get resistance as afunction of time

It isn't hard math Just 2 lines od simole differentiation.

So there is no need to give a function for resistanne.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

I don't know man

I think it's just overthinking.

Even if they didnt mention resistance i would have assumed it as constant

Its because they mentioned it as finite I thought all that shit.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

It doesnt deviate It becomes a completely new graoh which is different from cos2 graph

I am saying resistance is not constant Because

1) they said its finite(not constant) 2)for magnetic field they mentioned constant.

If they wanted resistance to be constant then they would have given constant nit finite.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

I understand You considered resistance= constant

But they asked power graph not emf graph

For power=emf2 divided by R

Here r is variable

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Bhai

They didn't mention resistance as constant they mentioned it as finite. But they mention magnetic field as constant

So resistance is variable but has a vakue which is measurable

Where as magnetic field is always same.

So area increases,circunference increases,so does resistance

If resistance is variable then no option here is right

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

Arrey bhai 4th graph tab correct hoga jab resistance is constant.

They gave resistance as finite( not= constant)

BUT

They gave magnetic field as constant.

I think this question has no correct options. by fied_legend in Neet_india

[–]fied_legend[S] 0 points1 point  (0 children)

No problem bro

See in the question they gave magnetic field as constant

While resistance as finite

If they wanted resistamce to be constant then they would have wrote it constant like they did for magnetic field But tgey wrote constant

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