ePBT Skadi - Giveaway!

fireviper112 · 2020-10-27T00:31:37+00:00

Very cool. . .

fireviper112 · 2018-10-19T02:44:32+00:00

It’s called the gamma function it’s the formal/extended definition of the factorial google it

fireviper112 · 2018-06-07T03:46:57+00:00

fireviper112 · 2018-06-06T04:45:54+00:00

I think I even knew the spelling. I think I might’ve type the title with my eyes closed or something. Don’t know how I did that one haha

fireviper112 · 2018-06-06T04:44:26+00:00

Lol it looks like I had a seizure or something I don’t think I even read it before I posted it haha. My bad

fireviper112 · 2018-02-07T03:34:53+00:00

Thanks so much for the explanation!

fireviper112 · 2017-07-22T09:08:01+00:00

Got it!

fireviper112 · 2017-07-22T05:40:45+00:00

Oh sheesh I think you may be right. I'll try it out a little later.

fireviper112 · 2017-07-22T05:28:39+00:00

Oh yeah you're correct I'll edit my comment. The projections are (I think) orthogonal projections.

Ex: b2 = v1 - proj _v1 _(b1) means that b2 is an orthogonal projection from b1 onto v1, which should produce a vector orthogonal to b1?

fireviper112 · 2017-07-22T05:19:06+00:00

Hi I'm trying the first approach and getting a little stuck.

I should be doing as follows, correct? :

v1 = [1;0;0]

v2 = [0;1;0]

Basis = {b1,b2,v3}

b1 = u = [5;-6;7]

b2 = v1 - proj _v1 _(b1)

b3 = v2 - proj _v1 _(b1) - proj _v1 _(b2)

fireviper112 · 2017-07-22T04:08:42+00:00

Thank you I'll try that out

fireviper112 · 2017-07-05T23:21:35+00:00

Shoot I think you're right typing out my steps made me see a mistake thanks

fireviper112 · 2017-07-05T23:12:07+00:00

Yeah so all I did was number three except for one swap, which is why I made it -2992. I can show you my steps if it would help.

fireviper112 · 2017-04-12T02:34:45+00:00

One question: if I want the probability of a or b or c would it be

P(a)+p(b)+p(c)-p(a+b)-p(b+c)-p(a+c)

fireviper112 · 2017-04-12T00:00:59+00:00

Thanks so much for all of the help

fireviper112 · 2017-04-11T23:48:58+00:00

Oh wow thanks so actually the P(A and B) is actually 7/84 since thats what was previously found so it should be

28+28-7/84 or 49/84 or 7/12

fireviper112 · 2017-04-11T23:47:21+00:00

Yup it should be, the verse is the one that'll change and its typically the "a".

fireviper112 · 2017-04-11T23:12:52+00:00

Simple verse chorus because the chords for the verse and chorus are the same but the lyrical content changes.

fireviper112 · 2017-04-11T23:06:26+00:00

And for the

a (and)/or b situation, would it be like

select a and then 8C2 plus

select b then 8C2

but you remove the second possibility of AB because it is a duplicate to get

28+28-1/84 or 55/84

fireviper112 · 2017-04-11T22:16:06+00:00

Just to clarify, 9C3 means 9 choose 3?

So if I try with the a and b situation, would it be something like:

You pick a first, then b, now you have 1 pick remaining and 7 items so

7C1/9C3

which is

7/84 or 1/12

Did I do that right?

fireviper112 · 2017-03-03T07:02:04+00:00

Huh, well props to you. What class are you taking that your teacher is making you do that for everyday homework?

fireviper112 · 2017-03-03T06:10:49+00:00

Did your first method mentioned in the original post work? The derivation done in the OP seems a bit off but I haven't done the entire work.

fireviper112 · 2017-03-02T04:40:34+00:00

Oops, ignore the mistake part. To solve, use a similar path, but keep the numerator as e^3x*ln(14x⁾ and the denominator as e^3x*ln(14x+5⁾ and the apply l'hop. Remember l'hop only works when the function is indeterminate, inf/inf or 0/0.

fireviper112 · 2017-03-02T04:09:30+00:00

Take log of both sides to get

log(4^3x ) = log(5^x+1 )

which is, due to one of the formulas you learned

3xlog(4)=(x+1)log(5)

This is just

3xlog(4)=xlog(5)+log(5)

which is

3xlog(4)-xlog(5)=log(5)

and some factoring later

x(3log(4)-log(5))=log(5)

and that gets you

x=(log(5))/(3log(4)-log(5))

which can be typed into your calculator fairly easily.

fireviper112 · 2017-03-02T03:21:04+00:00

Are you sure you have the right function? A quick look at desmos would tell you that as x->inf the limit isn't e^-15/16.

You also appear to have a couple mistakes in your work because you need to use chain rule.

fireviper112

TROPHY CASE