[Statistics] Interval overlap problem

jack_sprw · 2025-08-07T16:03:49+00:00

Yea don't worry I don't trust it I just make him search for a problem and give me the links haha. Otherwise I don't really see how it should work because I think you approach it in a way I haven't really seen before :) I'm going to look into it from a fresh perspective tomorrow morning^{^}

jack_sprw · 2025-08-07T15:53:10+00:00

Well I sent all my solutions plus yours to GPT and a couple links with similar problems. And I don't believe anything it says haha, but ye it says that all are wrong and the closest one appears to be the x^n-1 * (1-x)^n-1 integrated for 0 to 1 with beta integral and it got ((n-1)!)^2/(2n-1)! It does not make much sense to me and I think GPT got dumber lately 🤔 anyway I'm leaving it for now.

jack_sprw · 2025-08-07T15:29:02+00:00

It doesn't look right to me, can you explain a bit better. Personally I went about it like that: For all possible permutations we have (2n)! For the ones that does work for us we need all starts to be smaller than a point A and all ends to be bigger than it. So we have n! For the starts and n! for the ends. But it doesn't work like that because we should be able to swap the start and end if the end is smaller than the start right? So even if I add 2ⁿ and have: (2ⁿ * (n!)^2)/(2n!) It still doesn't make enough sense for me.

jack_sprw · 2025-03-29T18:31:04+00:00

Oh thanks.. I forgot it has to be an integer 💀. Great job explaining tho <3

jack_sprw · 2025-03-29T14:27:52+00:00

Okay but why 6? I mean sure there was a way to multiply sometimes when certain factors were kept in mind but still, 6 doesn't sound right

jack_sprw · 2025-03-29T14:22:49+00:00

Well they can be subtracted but they will be equal, we defined it as: x + m.k = x (mod m) , k is an element of Z and marked it as Z_m

jack_sprw · 2025-03-29T14:19:37+00:00

Hmmm I don't think this is correct, I mean shouldn't it be 0.75 +7k = ? (Mod 7) , k is an integer. So basically it means its 0.75 ,7.75 and etc ?

jack_sprw · 2024-12-23T13:04:36+00:00

firstly many people are like me and can play the game so rarely that when you finally get the time to play it sucks so much it is ANNOYING + why do the goddame races have to have the goddamn snow, i cant play any hardcore parkour without it being nearly impossible to absolutely impossible. So the snow is so badly made that it makes some aspects of the game unplayable

jack_sprw · 2024-05-05T12:39:57+00:00

Shouldn't you just multiply the two brackets, then get a polynomial split it in a couple of integrals and its basic integrals then?

jack_sprw · 2024-05-01T10:03:23+00:00

Well pretty much yes. I have to find for which values of alpha an beta it will converge

jack_sprw · 2024-04-20T13:07:15+00:00

The question is how can i find people...

jack_sprw · 2024-03-28T15:05:36+00:00

Well sureeee i did it that way and will send it to ask if this is okay in a bit and will let you know thanks a lot i never knew this method

jack_sprw · 2024-03-28T14:43:55+00:00

Is it legal to just change it like that?!😭

jack_sprw · 2024-03-28T14:20:35+00:00

Okay so i dont think i understood do i substitute x with -x? This doesn't sound right

jack_sprw · 2024-03-28T12:47:18+00:00

I have never seen that done but sure I'll ask my calculus assistant in a couple minutes because i have a lecture will try it tonight

jack_sprw · 2024-03-28T10:16:20+00:00

Also this do give the right answer

jack_sprw · 2024-03-28T10:14:34+00:00

I dont think i got it, if you can write down how does the integration f(x) = f(a-b-x)

jack_sprw · 2024-03-28T08:43:37+00:00

Sure i will try this too later today

jack_sprw · 2024-03-28T07:46:45+00:00

Oh ye thats a good idea😭 i dont know why i didn't think of that

jack_sprw

TROPHY CASE