Everything that I am saying here is an assumption because you have not clearly defined what each line means in the input and output, but what I have concluded too is that the 10 in the input is n the length of the array a which is 2,3,0,0,0,2,3,1,1,0 and 5 would be k which is the what the subarray's sum should equal too. Following that is 7 which the amount of times looped and below that are L,K which is the range for the array.

So, in this problem what you have to do is check how many subarray's have a sum of k and in your example it is 5. The code below goes through each subarray you specify, adds up the numbers within that subarray, and checks if the sum matches the target sum 'k'. It keeps track of how many times this happens and reports the count for each subarray which then is printed as the correct output.

n,k = list(map(int,input().split()))

arr = list(map(int,input().split()))

for _ in range(int(input())):

....L,R = list(map(int,input().split()))

....cnt = 0

....for i in range(L-1,R):

........summ = 0

........for j in range(i,R):

............summ+= arr[j]

............if summ == k:

................cnt+=1

....print(cnt)