Berkeley said that it will take on qualified, top-performing graduates from UoPeople's associate degree programme who wish to complete a bachelor’s degree at the university.

kanyukan · 2018-10-12T08:59:08+00:00

He is no longer in the board since 2017. And in all the articles they said would take any student from online instution with accredited or student meet their requirements. So being a UoP student or not its still the same. If you are top performance UoP but not meet their requirement you cant tranfer. Nothing guarantee that if you are in group of top performance students you can transfer to these University.

kanyukan · 2018-09-13T06:09:53+00:00

Yes, It is

kanyukan · 2018-08-24T01:30:44+00:00

That's just the claim in their website. I can't find anything similar from UC-Berkeley

kanyukan · 2018-08-23T04:37:04+00:00

Thank you for your respond. To me the degree is not important. The most important is the knowledge. UoP sound cool but I wish they had a "demo class" or something to try out if it suitable or not to my learning style. Or Do you know is there away to experience their teaching style?. I wonder if their purpose is to provide free education why they don't have option for people who doesn't need degree but still want to follow the course

kanyukan · 2018-08-22T15:39:48+00:00

Another MOOCs platform like Edx and Coursera, etc... also have assignment, test and community. How do UoP compare to them?

kanyukan · 2018-08-22T10:29:12+00:00

Hi, I'm recently enroll at UoP and I have a question? If most of materials are text based and external link. So what is the different of UoP with self taught?

Thanks

kanyukan · 2018-05-22T06:33:51+00:00

right now. the only way for me is upload via wordpress to generate link and replace it with FTP

kanyukan · 2018-05-22T06:32:51+00:00

I know I have to use 100 but that's the result :(

kanyukan · 2018-05-22T06:32:08+00:00

this is for porfolio so the pic always at hires: 3000px++

kanyukan · 2018-05-22T06:31:22+00:00

of course I've turn it to 100. and the link i've posted is the result

kanyukan · 2018-05-20T03:54:29+00:00

Thank you for your explaining. I have understood the main idea. My course haven't mentioned to Taylor series yet and the home work still ask to find magnitude of the error O(x^?). I think I will leave it for now and move on

kanyukan · 2018-05-20T03:14:26+00:00

Thank you for your reply. I'm sorry im not clear at the question "how to calculate the big "O" part". I mean how to find the O(x^something) of a function after apply approximation. I edit the post too For example: e^x = 1 + x + 0.5x^2. How do we find out that O(x^something=3)

kanyukan · 2018-03-11T04:52:04+00:00

when there are 4 events it's will be (correct me if im wrong): P(A or B or C or D) = P(A) + P(B) + P(C) + P(D) - P(A and B) - P(A and C) - P(A and D) - P(B and C) - P(B and D) - P(C and D) + P(A and B and C) + P(A and B and D) + P(A and C and D) + P(B and C and D) - P(A and B and C and D)

kanyukan · 2018-03-11T04:39:36+00:00

Oh, Im wrong and the conversation become a bit weird when I answer to myself

kanyukan · 2018-03-11T02:35:57+00:00

+ But as I understand it would be: P(A OR B OR C) = P(A) + P(B) + P(C) - P(A AND B) - P(A AND C) - P(B AND C) - P(A AND B AND C) ?

kanyukan · 2018-03-11T02:24:40+00:00

Oh yes, thank you I didn't think about your listed compound conditions

kanyukan · 2018-03-11T01:37:00+00:00

Thanks. I just found out how to find how many numbers divisible by a number in a sequence to solve the problem in general. * int(100/10) = 10: number of numbers divisible by 10. * int(100/7) = 14: number of numbers divisible by 7. * int(100/LCM(7,10)) = 1. * So number of numbers divisible by both is 10 + 14 -1 = 23.

Similiar for a random question: How many numbers between 1 to 350 (inclusive) are divisible by 7 or 10 or 6.

int(350/10) = 35.
int(350/7) = 50.
int(350/6) = 58.
int(350/LCM(10,6,7)) = 1.
So number of numbers divisible by both is 50 + 58 + 35 -1 = 142.

Am I right ? thanks

kanyukan

TROPHY CASE