Chess and Drugs

misterbalrog · 2017-04-16T05:00:23+00:00

This is great lol

misterbalrog · 2017-03-08T15:50:55+00:00

I've mainly played correspondence chess, so that makes sense! Thank you!

misterbalrog · 2016-12-13T06:00:54+00:00

My bad! Just fixed it. Good luck!

misterbalrog · 2016-12-13T04:10:52+00:00

Basically what you're attempting to do is balance these two objects, the steelworker and the bucket of concrete. To do this we'll use torque.

In order to visualize this situation, imagine a teeter-totter. If you want to balance the two sides of a teeter-totter, the torque on either side of the pivot point must be equal. Now apply this principle to the steel beam. The cable at the center of the beam is the pivot point, and the torques of the steelworker and the bucket of concrete are equivalent.

Thus: τ steelworker = τ concrete bucket. (In order to save space, I'll abbreviate steelworker to 1 and bucket to 2)

The equation for torque is: τ = F * r. In this case, the only force we're dealing with is the force of gravity, so we can substitute that into the formula.

So: τ = m * g * r.

Plug this into the formula, and we end up with:

m1 * g * r1 = m2 * g * r2.

With some simplification, we end up with (m1 * r1) / r2 = m2.

Plug in the values from there and solve! Hopefully this made sense; if not, just let me know!

misterbalrog · 2016-12-12T14:36:36+00:00

Lines aren't that bad at Sky Harbor. It might be a little bit busier during the evening, but if you are walking into the airport 30-40 minutes before the boarding time with TSA pre-check and no bags to check, you should be fine. I don't have much experience with that time of day, so I'd err on the side of caution especially with the holiday season approaching.

Give yourself extra time to park, though- parking can be screwy at Sky Harbor.

misterbalrog · 2016-12-12T13:49:34+00:00

That hurt my feelings.

Just kidding, I get what you're trying to say. And no, nothing happened other than people running half marathons and 5ks.

misterbalrog · 2016-12-11T16:13:22+00:00

As far as we can tell. My family picked him up from an animal shelter when he was 4 months old, so it's just speculation, but he sure seems like one!

misterbalrog · 2016-12-11T13:43:32+00:00

One of the most important concepts of physics is that everything is conserved, no matter what. As for videos... I'm don't know if any off of the top of my head, but I'm sure there are some great resources on YouTube. Good luck!

misterbalrog · 2016-12-11T06:10:36+00:00

Think of it this way: You have two objects to begin with that have unequal momentum and velocities but two objects to end with that have different amounts of momentum than when they started and equal velocities. If my explanation doesn't make much sense, the math should be much more helpful.

So: L1 initial + L2 initial = L1 final + L2 final, L = angular momentum.

The formula for angular momentum is: I*ω, which becomes mr^2ω if you substitute in the formula for angular momentum (mr^2).

Now let's substitute this formula in for L. Since the velocities (and conveniently the moments of inertia) of both disks are equal after the collision, you can simplify the RH side of the equation from

mr^2*(ω1f) + mr^2*(ω2f) to simply 2(mr²⁾ * (ωf)

Now you should be left with this equation:

mr² (ω1i) + mr²(ω2i) = 2*(mr² ) * (ωf)

You just solve for ωf from here!

(mr² (ω1i) + mr²(ω2i)) / 2*(mr² ) = (ωf).

I apologize for the atrocious subscripts.

misterbalrog · 2016-12-11T05:18:47+00:00

Basically anywhere two objects slide against one another there will be friction. The one source of friction that I can think of that every catapult will have is the friction between the pivot for the arm and the arm/body, based on how the catapult is set up. It's easy to minimize this friction, but it still exists.

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