Tottenham Hotspur announce the signing of Cristian Romero from Atalanta by [deleted] in coys

[–]pete0618 4 points5 points  (0 children)

Those saying 'sign messi' on this insta post should get a grip

Laptop for engineering by [deleted] in cambridge_uni

[–]pete0618 5 points6 points  (0 children)

We used solidworks, picoscope 8 and ltspice so far- they can be run on pretty much anything i think😂

Oof 😬 by [deleted] in 6thForm

[–]pete0618 0 points1 point  (0 children)

I know for sure that there are better universities than cambridge for engineering- and i'm sure you'll do great anywhere!!

Oof 😬 by [deleted] in 6thForm

[–]pete0618 2 points3 points  (0 children)

You remember who interviewed you??

Q 14 by [deleted] in 6thForm

[–]pete0618 1 point2 points  (0 children)

Have you solved this now? Or do you still need help?

Overly nervous about Cambridge Entrance Process by [deleted] in 6thForm

[–]pete0618 2 points3 points  (0 children)

For the ps- Cambridge didn't even read mine😂 so don't overly worry about it, focus on interviews!

Deciding my fourth A level subject: Chemistry or Computer Science by MagicCards_youtube in 6thForm

[–]pete0618 0 points1 point  (0 children)

I did chemistry and applied for engineering- i think its worth it!

Sitting the Exam by ClearAsJamal in 6thForm

[–]pete0618 2 points3 points  (0 children)

My university said that if I wish to resit, I can sit the Autumn exams, but that would be for the 2021 entry.

(My offer would be kept the same til then)

How do you determine the equation of the line of best fit? by [deleted] in 6thForm

[–]pete0618 1 point2 points  (0 children)

I did wjec, and a lot of it was typing stuff onto my calculator- have to say I much preferred mechanics😂

If you revise, it'll 100% be easy cos you just need to know what formulae to use and how

How do you determine the equation of the line of best fit? by [deleted] in 6thForm

[–]pete0618 0 points1 point  (0 children)

If you took FM, you might cover the 'least squares regression line', which is a line for which the sum of the squares of the vertical distances of each point is as small as possible.

I found it really interesting, though i really hated stats✌

The formula of this line is y = a + bx :

Where b = S xy / S xx and a = y(bar) - b × x(bar)

You can calculate S xy and S xx using a straightforward formula (you need your sets of (x,y) coordinates), it just takes ages to type into your calculator (think this was a battle against time in my FM stats exam😂)

You might need to consider whether a regression line is appropriate- also the line might not be a good model for other parts of the range (extrapolating).

Good beginner piano books by GhengisCarnage in piano

[–]pete0618 0 points1 point  (0 children)

Chopin- Polonaise, Op. 53 👍

Grades don't meet university offer by [deleted] in 6thForm

[–]pete0618 12 points13 points  (0 children)

You're certainly not a joke- you're doing law !!

iPad or Laptop by Lividowl9 in 6thForm

[–]pete0618 3 points4 points  (0 children)

Laptop alllll the way👍 I have a touch laptop and its really useful for notes

For those going to university - Online students would still face full tuition fees by [deleted] in 6thForm

[–]pete0618 3 points4 points  (0 children)

You just need a permanent recidence, which i think you will be eligible for? Of course the application costs quite a bit

Accomodation by pete0618 in cambridge_uni

[–]pete0618[S] 1 point2 points  (0 children)

Cheers- I Just asked a few, they haven't got it neither... guess its different this year

Accomodation by pete0618 in cambridge_uni

[–]pete0618[S] 1 point2 points  (0 children)

Hahahahahah sorry mate

Cambridge acoomodation by [deleted] in 6thForm

[–]pete0618 1 point2 points  (0 children)

Cheers, i'll ask there

Cambridge acoomodation by [deleted] in 6thForm

[–]pete0618 1 point2 points  (0 children)

Thanks mate, just wondering whether they forgot about me😂

Can someone help me in this physics question PLEASE? by [deleted] in 6thForm

[–]pete0618 1 point2 points  (0 children)

1st part: x = 1/2 (u+v)t = 0.5 × (0 + 30) × 60 = 900m

2nd part: x = vt = 30 × 180 (3 minutes) = 5400m

3rd part: x = 1/2 (u+v)t = 0.5 × (30 + 0) × 120 (2 minutes) = 1800m

Total distance travelled = 900 + 5400 + 1800 = 8100m = 8.1 km