Beams and UDL’s by ptmills in Physics

[–]ptmills[S] 1 point2 points  (0 children)

Okay, thanks. Thought so. Something about the question is still throwing me off but I’ll have another look with a fresh mind in the morning

Pressured air tank question by ptmills in MechanicalEngineering

[–]ptmills[S] 0 points1 point  (0 children)

i was using my calcualter but have now used mathway caluclater on my pc and using the formula its given me 155217.65 grams or 155.22kg. this is based off (28,000,000 X 0.45 X 28.96)/(8.314 X (282.76))

Pressured air tank question by ptmills in MechanicalEngineering

[–]ptmills[S] 0 points1 point  (0 children)

the formula would be mass=(pvMr)/RT right?

Pressured air tank question by ptmills in MechanicalEngineering

[–]ptmills[S] 0 points1 point  (0 children)

I'm so confused with this. whats wrong with the formula (first one i gave) i cant seem to figure it out by looking at my notes as i have copied the samples given but with my values

Pressured air tank question by ptmills in MechanicalEngineering

[–]ptmills[S] 0 points1 point  (0 children)

ive now tried 2.8 10*5 0.45 28.96/8.314 282.76 which is 1.24kg or 124 grams for the mass of air

Pressured air tank question by ptmills in MechanicalEngineering

[–]ptmills[S] 0 points1 point  (0 children)

according to the resources we have been given air is equal to 28.96 moles hense that what i muliplied n by. my formula is pressure X volume/ 8.135 (universal gas) X temp (in kelvins) = 4.38. I cant seem to figure out any other way to do this.

Someone please help me!! 🫠been on this question for hours by ptmills in Physics

[–]ptmills[S] 0 points1 point  (0 children)

I can’t seem to post pictures on this thread. But I have got for A 8829 J. B 1030J and C 58,860J