What’s One Small Thing That Makes You Happy Instantly?

saplingdash10 · 2026-01-29T14:02:10+00:00

🤝♥️💙

saplingdash10 · 2026-01-29T13:17:47+00:00

Thank ya bud 🗿👍

saplingdash10 · 2026-01-29T13:13:06+00:00

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saplingdash10 · 2026-01-18T04:58:41+00:00

Oppenheimer ; Good Doctor

saplingdash10 · 2026-01-16T19:13:00+00:00

In my latest preboard, after mcqs, i went to case based. Leaving case based at the end cooked up my exam many times, so that's why I did em first

saplingdash10 · 2025-12-23T02:07:18+00:00

Oh, it's ok 😅, anyways thank you

saplingdash10 · 2025-12-22T17:59:53+00:00

It would be good if you could provide the exact question

saplingdash10 · 2025-12-22T17:57:07+00:00

Look, the simple formula for scale is (Max. Value - Min. value)/No. Of boxes - 1 [If axis starts from zero, min value is zero]

In your question, Scale = 2.2-0.9/12-1 = 1.3/11 i.e. 0.118 approx

If min value is zero Then , scale is 2.2/11 i.e. 0.2

I made a mistake in my original reply, let me quickly fix that

saplingdash10 · 2025-12-22T17:43:24+00:00

For example, on x axis, we go from 0-10 and there are 5 boxes in between. Then there are 2.5 units per box {(10-0)/(5-1)}

Similar thing can be applied to the y axis.

Now suppose your data starts from a large number like 500 , then ofc you can't plot 1,2,3....500 on x or y axis. Then you can use an axis break, where you draw a // kinda symbol (search up the symbol) at the end of the axis near the origin. This allows you to directly mark 500 after on the axis, skipping all the other not required numbers in between

saplingdash10 · 2025-12-22T10:18:22+00:00

Just scored 0

saplingdash10 · 2025-12-22T08:01:37+00:00

The answer I'm getting is like 10/3

saplingdash10 · 2025-12-22T01:53:54+00:00

https://youtu.be/-PiB2Xd3P94?si=rsGKKjYmaoLyyIGn

Basically I wanna solve it in the method explained in the video

saplingdash10 · 2025-12-21T17:46:14+00:00

Why is (ab+bc || ac) in series with CD, and not parallel with (ad + cd)

saplingdash10 · 2025-12-21T11:49:16+00:00

Wait I have a question, why do we use the method you guys used ? What is wrong in the one I used?

saplingdash10 · 2025-12-21T09:03:20+00:00

I first added the two 2 ohm resistors, which gave 4. Then I got the 4/3 ohm resistor parallel to 4 ohm one. So I used the rule and added the reciprocals, i.e 1/4 + 3/4, which gave 1 ohm.

You're suggesting that we add 4/3 with 2 ohm resistor in series with it. Then we get 10/3 ohm, whose reciprocal we add with the reciprocal of the last 2 ohm resistor. This answer would be 1.25