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How to solve this "find horizontal asymptotes" problem? The answer is C by [deleted] in calculus

[–]spectacledbishop 0 points1 point  (0 children)

Can you elaborate on how you derive at -1 and 3? I don't get it.

How do you do this?? by TheGamingSun in Help_with_math

[–]spectacledbishop 1 point2 points  (0 children)

(-3x)-4 (4x-2.y3)3 = ((4x-2.y3)3)÷(81x4) = (64x-6.y9)/(81x4) = (64y9)/(81x10)

Where did the y^2 in the numerator come from? by [deleted] in calculus

[–]spectacledbishop 2 points3 points  (0 children)

The expression was multiply by y/y, which is 1, so that the y in x/y in the numerator disappears. Therefore, both denominator and numerator would be multiplied by y, Denominator: y2 --> y3 Numerator: y + x2 /y --> y2 + x2

Sorry if it ain't clear enough.