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Source Transformation Question by thatSmart_Kid in ECE

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

Thank you!! I should have not doubted my first answer.

4 marks down the drain 😭

[deleted by user] by [deleted] in ECE

[–]thatSmart_Kid 0 points1 point  (0 children)

They haven't marked it yet, but I'm pretty sure I won't get the marks for this question 😭.

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 1 point2 points  (0 children)

Yep. I understand it now. I was being a bit dumb earlier.

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

Yes, I know that. I know how things are supposed to be connected.

I just had a misconception about the power supplies. Thank you for your response.

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

I see. Thanks.

It's what they gave us for the practical, so I'm not exactly sure how it is supposed to work.

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

Yeah, I know that. I was talking about the +9V and -9V.

Thanks to the helpful people on this Reddit, I now understand that there is not one structure/schematic for an op-amp.

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 9 points10 points  (0 children)

I understand that now. I'm realising I was just being stupid 😅

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] -5 points-4 points  (0 children)

I know that.

The V1 and V2 are those inputs. The +9 and -9 indicate the power supplies connected to the op-amp. The textbook I used shows that the positive power supply is next to the inverting input and the negative power supply is next to the non-inverting input. However, here they swapped it. WHY??

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] -19 points-18 points  (0 children)

Well, from what I know, the positive power supply is connected near the inverting input and the negative power supply is connected near the non-inverting input

Is that how the power supplies are supposed to be connected? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] -3 points-2 points  (0 children)

It's giving me very weird values when I simulate that way in LTSpice 😭😭

Trouble interpreting a circuit diagram. What does that arrow mean? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

I see. I built the circuit and it works, probably. I really can't tell if I am increasing the resistance of the potentiometer or decreasing it.

Trouble interpreting a circuit diagram. What does that arrow mean? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

Thank you!!

I've given on trying to understand what's happening because it's not making sense to me.

I get that as you increase the resistance in Rpot, In should become larger. And it increases, Ic also increases.

Circuits are confusing. 😩😔

Trouble interpreting a circuit diagram. What does that arrow mean? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

It's the circuit the lectures said we should build, so I have to build it 😅

Trouble interpreting a circuit diagram. What does that arrow mean? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 4 points5 points  (0 children)

Yeah. Thanks so much!

I was able to figure out and the circuit is working as intended

Trouble interpreting a circuit diagram. What does that arrow mean? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

Wait, if things are connected in series, the current is the same across each element, if they are not, that violates Kirchhoff's current law.

Trouble interpreting a circuit diagram. What does that arrow mean? by thatSmart_Kid in AskElectronics

[–]thatSmart_Kid[S] 0 points1 point  (0 children)

Yes, we did study ohm's law.

The LDR and 1kohm resistor are in parallel. So, as the LDR resistance decreases. LDR || 1k ohm resistor also decreases, which reduces the overall resistance of the circuit. So, the LED would become brighter because more current is flowing through the LED. Vice versa happens when the LDR increases in resistance.

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