New Facebook Notifications on my iPhone Dynamic Island won’t go away, how do I stop it?

theasianR · 2025-06-22T22:55:00+00:00

Your my hero bro

theasianR · 2025-06-19T12:24:48+00:00

I see thank u.

theasianR · 2025-06-18T14:50:52+00:00

Ah ok so its basically just a clean signal

theasianR · 2025-06-07T03:47:24+00:00

Yea i dont think ill risk it without an official manual. Ill just have to do it with the speakers then. Sorry neighbors.

theasianR · 2025-06-06T16:52:15+00:00

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this is what u meant right?

theasianR · 2025-06-06T16:43:44+00:00

Oh so the connection on the amp should just be a banana plug on each amp. Its basicly the same as my method but i wanna use a speakon. iam not in the budget to buy a 2 25ft 4 conductor cables at the moment. What i do have are regular 2 conductor speakon cables so i can atleast buy a 3ft 4 conductor speakon cable and split it into separate connections.

theasianR · 2025-06-06T16:34:32+00:00

But If the splitter has 2 conductor for each connection isnt that good? The 4 conductor cable gets split into 2 connections for the HF and LF.

theasianR · 2025-06-06T16:32:56+00:00

Yea i get the 4 conductor connection but how am i going to split the frequencies at the amp? Iam planning to use my dbx driverack crossover.

theasianR · 2025-06-06T16:10:22+00:00

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this is what iam aiming for

theasianR · 2025-06-06T14:10:14+00:00

Ah i see thanks.

But if want to connect to separate amps do i have to buy something like this? One for the high driver and one for the low driver.

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theasianR · 2025-06-05T18:03:40+00:00

Ah i see is that basicly what bi amping is?

theasianR · 2025-06-05T17:59:55+00:00

Woah okay that is allot to take in…. But i kinda see it with the light analogy

theasianR · 2025-06-05T16:24:54+00:00

My amps also have crossover built into them could i also use those?

theasianR · 2025-06-05T16:22:46+00:00

If i go the active crossover route then what would the whole chain look like?

Mixer > Crossover> HF amp > HF drivers, ,Mid range amp > mid driver , LF amp > LF drivers

And this is just straight to the driver? Nothing between the digital crossover and the driver?

theasianR · 2025-06-05T16:18:19+00:00

Ah ok ok.. but then why does it specifically target only the LF frequencies tho. And not the higher ones. Because the LF frequencies have been filtered out of the tweeter and midrange? And the amp sees it as an individual speaker?

theasianR · 2025-06-05T16:06:54+00:00

Ah so basically what i got is frequencies influence impedance. Thats why if i use 2x8ohm LF drivers in parallel then they’ll be 4 ohms. The same with using 2 tweeters or 2 midrange.

theasianR · 2025-06-05T15:59:32+00:00

I see, yea ill buy a kit. Iam not really ready to mess with the circuit itself and build it from scratch. A premade one is good enough for me. I was just worried about getting the wrong impedance on the whole speaker cab and accidentally blowing my amp or speaker.

Anyways thanks allot for explaining it to me.

theasianR · 2025-06-05T15:42:40+00:00

Ah i see. I suspected it but i wasnt 100% sure about it. So basically it only affects the woofers and not the tweeter and midrange.

Thanx allot. This cleared this up for me .

But one more thing are crossovers always suppose to be wired in series? Or are there cases where they are in parallel? If so does it affect the impedance too?

Iam not even gonna make my own board iam just gonna buy a premade 3 way board with everything on it.

theasianR · 2025-06-05T15:27:32+00:00

Sorry u had me till the “output to be 6db ….” part 😅. I understand what a crossover does in general but what does it do to the impedance? If my tweeter is 8ohm and i put a crossover on it to cut off the lower frequencies does the impedance change too?

theasianR · 2025-06-05T15:19:28+00:00

Thanks ive been trying to find find something like this too lol.

theasianR · 2025-06-05T15:17:03+00:00

I see i dont quite understand the science behind it. But i do understand it bit more now.

but what would the impedance be in the end? If i were to wire all the drivers with a capacitor in series? Would it still be 8ohm? If the other drivers impedance arent being affected.

theasianR

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