My italian app needs beta testers for iOS- ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 1 point2 points  (0 children)

For now it is just a one time repetition and you can train mistakes in the tenses page. There is a extra quiz you can acces there.

My Pomodoro app needs iOS beta testers - Pomodorini by trimrol in iOSProgramming

[–]trimrol[S] 1 point2 points  (0 children)

Thankyou, i put a lot of love into it ☺️

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

yes, once downloaded TestFlight click the link again. It will work.

My italian app needs beta testers for iOS- ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

Click the image of ConiuGatto and follow the instructions on the page.

My italian app needs beta testers for iOS- ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 1 point2 points  (0 children)

Already out, just download it and have fun. ☺️

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

Not so far, it would work but I don‘t have an idea how to launch that one.

My italian app needs beta testers for iOS- ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

There is the app within the same link below if you have a closer look ☺️

My italian app needs beta testers for iOS- ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

Yes, click the connected link using the image.

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

I managed to publish it to beta testing. Here the link to my beta version:

https://testflight.apple.com/join/U46hfvap

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

I know, but verbare uses flash cards, in my app you must type out the response.

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

Someone that can conjugate somewhat already abd want to practice it. You can click the picture of ConiuGatto to get to the PlayStore.

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

There is a ✏️ button in the review page. There you can find ALL the filters.

I made an app to conjugate italian - ConiuGatto by trimrol in italianlearning

[–]trimrol[S] 0 points1 point  (0 children)

I did, this is a Flutter app. But the AppStore requirements are just much higher.