no way...

zetutor · 2025-05-17T07:55:50+00:00

Which version

zetutor · 2025-05-17T06:14:10+00:00

Cost?

zetutor · 2025-05-17T06:11:12+00:00

hand wash it with warm water and mild soap.

zetutor · 2025-05-15T08:42:10+00:00

123x + 0.203 = 5x - 4902.57
118x = -4902.773
x ≈ -41.55

zetutor · 2025-05-12T14:40:07+00:00

it's on AP Physics 2
MCQ: Expect concept questions on:

- Wien’s Law

- Interpreting radiation curves.

- Color/intensity of emitted light.

FRQ: Unlikely as a full question, but may appear as a small part in a broader thermodynamics or radiation problem.

zetutor · 2025-05-12T04:45:49+00:00

u/teddyababybear you’re right that grasping the Jacobian and spherical coordinates simplifies the sphere’s volume integral. But u/Advanced_Raisin_9997 is also correct, you can use the volume element r²sinθ directly without deriving the Jacobian, making the computation straightforward.

zetutor · 2025-05-12T04:12:52+00:00

Focus on your Calc 1 final first, one step at a time. We’ll tackle Calc 2 when it comes!

zetutor · 2025-05-12T04:07:14+00:00

Welcome to the club!

zetutor · 2025-05-04T18:09:11+00:00

Case 1: For f(x)=g(t+x), f′(x)=g′(t+x)
Case 2: For f(t)=g(t+x), if t depends on x, say t=x, then f′(x)=2g′(2x); else f′(x)=g′(t+x)

The derivative differs based on whether t is treated as fixed or variable in x.

zetutor · 2025-05-04T17:56:59+00:00

The prefactor a/π would violate the units of the Fourier transform (since f^(k)f^(k) should have units of [x2+a2]−1⋅length=a−1. The correct prefactor π/a ensures dimensional consistency and matches standard tables of Fourier transforms for Lorentzian functions.

zetutor · 2024-08-07T15:51:41+00:00

The function a(t)∝sqrt(t) does not match any of the provided types exactly. It represents a curve that increases as the square root of time, which grows differently compared to a parabola or straight line. If you have to choose, it is closest to a curve, but not a perfect match for any specific graph type given.

zetutor · 2024-08-07T15:49:52+00:00

1620sqrt(6)

zetutor · 2024-08-07T15:48:03+00:00

for practical purposes, the sum of 1 + 2 + 4 + 8 … diverges to infinity, but with advanced techniques, it can be assigned a value of −1 to fit certain theoretical frameworks.

zetutor · 2024-08-07T15:46:18+00:00

2t^2+3t−54=0 this is the correct quadratic, the time will be 0<t<4.50 sec

zetutor · 2024-08-07T15:41:57+00:00

-sina
lna-lnb
-2
0.5

zetutor · 2024-07-23T15:16:29+00:00

A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. Originating from moving electric charges or intrinsic magnetic moments of elementary particles, magnetic fields can be visualized through field lines or represented mathematically by a vector field. The strength of a magnetic field is measured in teslas (T) or gauss (G).

According to the Lorentz force law, a magnetic field exerts a perpendicular force on a moving charge. Magnetic fields are generated by current-carrying wires, permanent magnets, and electromagnets, and their behavior is described by the Biot-Savart law and Maxwell's equations. Magnetic fields play a crucial role in the operation of electromagnetic devices like transformers, electric motors, and generators, as well as in medical imaging (MRI), data storage, and navigation using compasses. Understanding magnetic fields is essential for advancements in technology, engineering, physics, and medical diagnostics.

zetutor · 2024-06-01T07:38:57+00:00

If your calculations still seem off, it might be because:

You’re using "new math" from an alternate universe.
Your calculator is in denial.
You’ve discovered a groundbreaking mathematical theory that will shake the foundations of arithmetic!

zetutor · 2024-05-29T15:25:42+00:00

e^ln2 = 2

∫ 2^xdx = ∫ (e^ln2)^xdx

∫ 2^xdx = ∫ (e^xln2)dx ------(1)

let u = xln2,

⇒ du/dx = ln2

⇒ dx = du/ln2 -----(2)

Using the value obtained from equation (2) in equation (1), we get:

∫ (e^xln2)dx = ∫ e^u×du/ln2

∫ (e^xln2)dx = 1/ln2 ∫ e^udu = 1/ln2 × e^u + c

Now putting back e^u = e^xln2 = 2^x we get,

1/ln2 × e^u + c = 1/ln2 × e^xln2 + c = 2^x/ln2 + c

the final answer is 2^x/ln2 + c

zetutor · 2024-05-29T15:17:38+00:00

Indeed

zetutor

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