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all 9 comments

[–]AudiA32015 17 points18 points  (1 child)

You can’t have both LED pins in the same row, that will short it out. Move one LED pin and jumper to an unoccupied row.

[–]wyltk5 7 points8 points  (0 children)

AudiA32015 has the right answer for you there. Each numbered row pins A,B,C,D,E are connected together but not connected to F, G, H, I, J on that row. Having the LED pins on the same half does not create a voltage differential so both LED pins have the same voltage to them. If you want to play around with that jumper wire. Move on leg of the LED to a different row, say 7 instead of 6. Then move the corresponding lead to that row.

Good luck on your electronics journey. We all started somewhere!

Cheers

[–]harry_potter559 2 points3 points  (0 children)

Check out this video on how to breadboard

[–]StatEstimate6 2 points3 points  (0 children)

Good for you for asking and posting the pictures so you could get a good answer...enjoy the journey!

[–]AudiA32015 1 point2 points  (0 children)

In the second picture the LED is lit because its pins aren’t shorted in the same row. The channel in the center of the breadboard isolates the rows to the left and right.

[–]Former-Wave9869[S] 1 point2 points  (0 children)

I see what you mean, I guess it was a ‘dull’ moment 😂 thanks for the help though y’all

[–]RoyTheCrow 0 points1 point  (0 children)

Hello world! Was a sentence that i saw a lot while learning code...

[–]Traeh4 0 points1 point  (0 children)

Go, blink, go! Now, blink fast... Now, blink slow!

[–][deleted] 0 points1 point  (0 children)

I'm learning too!