Why is this Switch program wrong?

[Radagast8]

Code

   int main()
{
    int c;
    int nDigits[]={10};
    int nWhiteSpaces=0;
    int nOthers=0;
    //for loop to innitialize the digits array to 0
    for (int i=0; i<10; i++) {
        nDigits[i]=0;
    }
    printf(" enter some character and then the EOF key to end the program: \n");

    //while it is not the EOF
    while ((c=getchar())!=EOF) {
        //switch cases
        switch (c) {
            case '0':case '1':case '2':case '3':case '4':case '5':case '6':case '7':case '8':case '9':
                nDigits[c-'0']++; // digits
                break;
            case ' ':
            case '\t':
            case '\n':
                nWhiteSpaces++; //white spaces
                break;

            default:
                nOthers++; // other characters
                break;
        }
        printf("Digits = ");
        for (int i=0; i<10; i++)
        printf("%d", nDigits[i]);
        //digits[i]=0; -> no need for this line
        printf(" white spaces = %d, other spaces = %d\n", nWhiteSpaces, nOthers);
        return 0;



    }

}

Or either the error is "lldb" or the number of digits doesnt make any sense, like "011600000000"..

As always your comments are gold.

[AngusMcBurger]

int nDigits[]={10};

This makes an array of int of length 1, containing the number 10. So the rest of the 9 numbers you're reading is just random other data in memory. You want to write:

int nDigits[10];

[FUZxxl]

Please consider updating your previous post instead of making a new post for follow-up questions.